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mafiozo [28]
3 years ago
15

11. In TLC analysis of ferrocene and acetylferrocene (on silica TLC plate) which prediction is correct: A) ferrocene is more pol

ar and moves higher up the plate (higher Rf value) B) Acetylferrocene is more polar and moves higher up the plate (higher Rf value) C) ferrocene is less polar and moves higher up the plate (higher Rf value) D) Acetylferrocene is less polar and moves higher up the plate (higher Rf value)
Chemistry
1 answer:
yaroslaw [1]3 years ago
8 0

Answer:

Alternative C would be the correct choice.

Explanation:

  • The dual compounds were evaluated on something like a TLC plate through three separate additives in conducting a TLC study of ferrocene versus acetylferrocene.
  • The polar as well as nonpolar ferrocene where nonpolar is about 0.63 with the maximum R_f value, and indeed the polar is somewhere around 0.19 with R_f.
  • TLC plate (30:1 toluene/ethanol) established with.  

The other three choices are not related to the given circumstances. So that option C would be the appropriate choice.

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Molar mass of FE2O3=2(55.85)+3(16)=159.7

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Compare the modern (electron cloud) model of the atom with Bohr’s atomic model. Which of these statements describe the two model
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B. Bohr’s model electrons cannot exist between orbits, but in the electron cloud model, the location of the electrons cannot be predicted.

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The bonds of the product store 27 KJ more energy than the bonds of the reactants how is energy conserved during this reaction
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<h3>What is the Exothermic reaction ?</h3>

An exothermic process releases heat, causing the temperature of the immediate surroundings to rise.

The bonds of the product store 27 KJ more energy than the bonds of the reactants, It means that energy has been absorbed by the surrounding as the product formed is more stable due to more stronger bond

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6 0
2 years ago
The hydrogen chloride (HCl) molecule has an internuclear separation of 127 pm (picometers). Assume the atomic isotopes that make
natta225 [31]

Answer:

the energy of the third excited rotational state \mathbf{E_3 = 16.041 \ meV}

Explanation:

Given that :

hydrogen chloride (HCl) molecule has an intermolecular separation of 127 pm

Assume the atomic isotopes that make up the molecule are hydrogen-1 (protium) and chlorine-35.

Thus; the reduced mass μ = \dfrac{m_1 \times m_2}{m_1 + m_2}

μ = \dfrac{1 \times 35}{1 + 35}

μ = \dfrac{35}{36}

∵ 1 μ = 1.66 × 10⁻²⁷ kg

μ  = \\ \\ \dfrac{35}{36} \times 1.66 \times 10^{-27} \ \  kg

μ  = 1.6139 × 10⁻²⁷ kg

r_o = 127 \ pm = 127*10^{-12} \ m

The rotational level Energy can be expressed by the equation:

E_J = \dfrac{h^2}{8 \pi^2 I } \times J ( J +1)

where ;

J = 3 ( i.e third excited state)  &

I = \mu r^2_o

E_J= \dfrac{h^2}{8  \pi  \mu r^ 2 \mur_o } \times J ( J +1)

E_3 = \dfrac{(6.63 \times 10^{-34})^2}{8  \times  \pi ^2  \times 1.6139 \times 10^{-27} \times( 127 \times 10^{-12}) ^ 2  } \times 3 ( 3 +1)

E_3= 2.5665 \times 10^{-21} \ J

We know that :

1 J = \dfrac{1}{1.6 \times 10^{-19}}eV

E_3= \dfrac{2.5665 \times 10^{-21} }{1.6 \times 10^{-19}}eV

E_3 = 16.041  \times 10 ^{-3} \ eV

\mathbf{E_3 = 16.041 \ meV}

8 0
2 years ago
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