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eimsori [14]
3 years ago
9

87 g of oxygen gas would occupy how many liters of volume at stp

Chemistry
1 answer:
loris [4]3 years ago
8 0
Number of mole : mass/ molar mass

87g/ (2 x 16) = 2.719 mol

volume = number of mole x molar volume
volume = 2.719 x 22.4
volume = 60.906 L
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Answer:

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H₂Tart  +  H₂O  ⇄  H₃O⁺   +  HTart⁻         Ka1

HTart⁻  +  H₂O  ⇄  H₃O⁺   +  Tart⁻²           Ka2

When we anaylse the base, we have

Tart⁻²   +  H₂O  ⇄  OH⁻  +  HTart⁻       Kb1

HTart⁻  +  H₂O  ⇄  OH⁻  +    H₂Tart          Kb2

Remember that Ka1 . Kb2  = Kw, plus pKa1 + pKb2 = 14

Kb2 = Kw / Ka1  →   1×10⁻¹⁴ / 9.20×10⁻⁴  = 1.08×10⁻¹¹

so pKb = - log Kb2   → - log 1.08×10⁻¹¹ = 10.96  

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3 years ago
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Step 3: Scoop a teaspoon of each substance in the jars, only adding one substance per jar. Stir it up!

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