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Kruka [31]
1 year ago
11

If a plank which is 10 feet long is cut into

Mathematics
1 answer:
Firlakuza [10]1 year ago
3 0

Answer:

If a plank which is 10 feet long is cut into two pieces and if one piece is x feet long,

Then the other piece will be (10 – x) feet long.

Here the value of the one piece is given as ‘x’ value

so the represent of the length of the other part will be (10 – x ) feet

know more about “ratio” here:

brainly.com/question/12024093

#SPJ9

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tresset_1 [31]
A and D because it is basically saying 3:36 so when you simplify it comes down to 1:12
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Problem Yoda Soda is the intergalactic party drink that will have all your friends saying, "Mmmmmm, good this is!" You are throw
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For 121212 guests we need 555 liters,for 363636 guests how many liters



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121212 555
363636 x

So 121212*x=363636*555
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Is negative 17/24th bigger or smaller than negative 11/12
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5 0
3 years ago
Bigger animals tend to carry their young longer before birth. The length of horse pregnancies from conception to birth varies ac
Shtirlitz [24]

Answer:

a) \mu -3\sigma = 336-3*6=318

\mu+-3\sigma = 336+3*6=354

b) For this case we know that within 1 deviation from the mean we have 68% of the data, and on the tails we need to have 100-68 =32% of the data with each tail with 16%. The value 342 is above the mean one deviation so then we need to have accumulated below this value 68% +(100-68)/2 = 68%+16% =84%

And then the % above would be 100-84= 16%

Step-by-step explanation:

Assuming this question : "Bigger animals tend to carry their young longer before birth. The  length of horse pregnancies from conception to birth varies according to a roughly normal distribution with  mean 336 days and standard deviation 6 days. Use the 68-95-99.7 rule to answer the following questions. "

(a) Almost all (99.7%) horse pregnancies fall in what range of lengths?

First we need to remember the concept of empirical rule.

From this case we assume that X\sim N(\mu = 336. \sigma =6) where X represent the random variable "length of horse pregnancies from conception to birth"

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

From the empirical rule we know that we have 99.7% of the data within 3 deviations from the mean so then we can find the limits for this case with this:

\mu -3\sigma = 336-3*6=318

\mu+-3\sigma = 336+3*6=354

(b) What percent of horse pregnancies are longer than  342 days?

For this case we know that within 1 deviation from the mean we have 68% of the data, and on the tails we need to have 100-68 =32% of the data with each tail with 16%. The value 342 is above the mean one deviation so then we need to have accumulated below this value 68% +(100-68)/2 = 68%+16% =84%

And then the % above would be 100-84= 16%

7 0
3 years ago
12
Stels [109]

Answer:

x = 1 Whole 1/3

Step-by-step explanation:

10001010100110010101001010101010111000100101010

3 0
3 years ago
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