A table can be represented with a linear function equation as y = mx + b, where m is the slope and b is the y-intercept.
<h3>How to Represent a Table with Linear Function?</h3>
Assuming we have a table of values as shown in the image attached below, to write an equation of linear function for the table, do the following:
Pick two pairs of values, say, (1, 5) and (2, 25) and find the slope (m):
Slope (m) = change in y / change in x = (25 - 5)/(2 - 1)
Slope (m) = 20
Find the y-intercept (b) by substituting (x, y) = (1, 5) and m = 20 into y = mx + b:
5 = 20(1) + b
5 = 20 + b
5 - 20 = b
-15 = b
b = -15
Write the equation of the linear function by substituting m = 20 and b = -15 into y = mx + b:
y = 20x - 15
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Answer:
The answer is D
Step-by-step explanation:
It will be slightly more than 15 because it is 15.707963267...
Answer:
The domain of function
is set of all real numbers.
Domain: (-∞,∞)
Step-by-step explanation:
Given:


the domain of both the above functions is all real number.
To find domain of :

Substituting functions
and
to find 

The product can be written as difference of squares. ![[a^2-b^2=(a+b)(a-b)]](https://tex.z-dn.net/?f=%5Ba%5E2-b%5E2%3D%28a%2Bb%29%28a-b%29%5D)
∴ 
The degree of the function
is 2 as the exponent of leading term
is 2. Thus its a quadratic equation.
For any quadratic equation the domain is set of all real numbers.
So Domain of
is (-∞,∞)
<span>you're given both arcs, minor and major, or near and far arcs, all you need to do, is really plug them in</span>