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algol13
4 years ago
8

Find the derivative of the following functions f(x) = x^7 - 2x^3 - 9x

Mathematics
1 answer:
Finger [1]4 years ago
8 0
Use the power rule,
d(x^n)/dx = nx^(n-1)

So
f(x)=x^7-2x^3-9x
f'(x)=7x^6-6x^2-9
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Answer:

  4) y = -3(x+2)^2 +4; y = -3x^2-12x-8; ABC=(-3, -12, -8)

  5) y = 0.5(x-1)^2-2; y = 0.5x^2-x-1.5; (h,k) = (1, -2)

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Step-by-step explanation:

Writing a quadratic equation through a set of points is most easily done using the regression function of a graphing calculator or spreadsheet.

4) see the first attachment

  y = -3(x+2)^2 +4 . . . vertex form

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__

5) see the second attachment

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  y = 0.5x^2 -x -1.5 . . . standard form

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6) see the third attachment

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  y = -0.3x^2 -1.2x -7.2 . . . standard form

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which will result in three linear equations for a, b, c. Those can be solved by any of the usual methods.

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