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labwork [276]
3 years ago
11

A deli served 1,288 sandwiches in 4 weeks. If it served the same number of sandwiches each day, how many sandwiches did it serve

in 1 day? Explain how you found your answer
Mathematics
1 answer:
Serggg [28]3 years ago
3 0
(write this) The deli served 322 sandwiches in one or each day. I found my answer by dividing 1288 by 4 my final answer was 322. Just to make sure this correct I multiplied 322 × 4.
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Which of the following states that if the product of two real numbers is zero,then either of the two is equal to zero or both nu
Lesechka [4]

Answer:

Zero Product Property

Step-by-step explanation:

If you have the following options:

A. Multiplication property

<u>B. Zero product property</u>

C. Identity property

D. Transitive property

3 0
2 years ago
Doug says that this clock shows 8:43.is he correct? Explain why or why not
Lena [83]
Depending on what the clock says yes and no.
4 0
3 years ago
Read 2 more answers
Ivanna paid $11.88 for a 2.38-pound bag of shrimp at one store. The following week, she paid $26.47 for a 5.08-pound bag at anot
stepan [7]

Answer:

2.38 lb bag = 4.99/lb   5.08 lb bag = 5.21/lb  The 2.38 is the better buy

Step-by-step explanation:

1.88/2.38 = 4.99

26.47/5.08 = 5.21

4.99 is cheaper than 5.21 so the 2.38 lb bag is better buy

8 0
2 years ago
Read 2 more answers
What is the coefficient of the x^5y^5- term in the biomial expansion of (2x-3y)^10
jasenka [17]

<u>Answer:</u>

 The coefficient of x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552

<u>Solution: </u>

The given expression is (2 x-3 y)^{10}

As per binomial theorem, we know,

(x+y)^{n}=\sum n C_{k} x^{n-k} y^{k}

Now here a = 2x, b = (- 3y) and n = 10 and k = 0,1,2,….10

Now x^{5}\times y^5 will be the 6 term where k =5

Now, \mathrm{T}_{6}=10 \mathrm{C}_{5} \times(2 \mathrm{x})^{(10-5)} \times(-3 \mathrm{y})^{5}=10 \mathrm{C}_{5} 2^{5} \times \mathrm{x}^{5} \times(-3)^{5} \times \mathrm{y}^{5}

So, the coefficient of x^{5} \times y^{5} \text { is }=10\left(5 \times 2^{5} \times(-3)^{5}\right.

10 \mathrm{C}_{5}=\frac{10 !}{5 ! \times(10-5) !}=\frac{10 !}{5 !+5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6 \times 5 !}{5 ! \times 5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6}{5 \times 4 \times 3 \times 2 \times 1}=\left(\frac{30240}{120}\right)=252

The coefficient of x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552

6 0
3 years ago
Help plz will mark brainliest........................
fredd [130]
It would be HL=I !!!!!!!!!!!!!!!!!!!! 
hope this helps
6 0
3 years ago
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