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xxTIMURxx [149]
1 year ago
9

60.5 x 0.052 in standard algorithm

Mathematics
1 answer:
suter [353]1 year ago
6 0

Step-by-step explanation:

es 3.146 espero haberte ayudado

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There are 15 pens and 10 pencils in a box. One object is selected at random and then replaced. Another is the selected. Find the
almond37 [142]

Step-by-step explanation:

1. P(pen then pencil) = 15/25 × 10/25 = 3/5 × 2/5 = 6/25

2. P(pen then pencil) + P(pencil then pen) = 6/25 + 6/25 = 12/25

3. P(pencil then pencil) = 10/25 × 10/25 = 2/5 × 2/5 = 4/25

4. P(at least 1 pen) = 1 − P(no pen) = 1 − 4/25 = 21/25

6 0
4 years ago
One cellular phone carrier charges 26.50 a month plus .15cents a minute. Another carrier charges 14.50 a month plus .25 cents a
Levart [38]
I'm going to use m for minutes
Cell carrier 1
0.15 per minute (0.15m)
$26.50 first, and then add on for every minute

cost carrier 1 = 0.15m + 26.50

carrier 2
0.25 per minute (0.25m)
$14.50 first, and then add on for every minute. 

cost carrier 2 = 0.25m + 14.50 

to find out when they cost the same, make the two costs equal to each other:

0.15m + 26.50 = 0.25m + 14.50

all that's left is to solve for m

0.15m + 26.50 = 0.25m + 14.50
subtract both sides by 0.15 m
26.50 = 0.2m + 14.50
subtract both sides by 14.50
12 = 0.1 m 
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m = 120

the phone carriers will have the same cost at 120 minutes


6 0
4 years ago
Read 2 more answers
Need now<br><br>find the discriminant of the following equation. 9x^2+12x+4=0
andrey2020 [161]

So to find the discriminant of a quadratic equation, the formula is b² - 4ac with a = x² coefficient, b = x coefficient, and c = constant. In this case, our equation is 12^2-4*9*4

Firstly, solve the multiplications and the exponents: 144-144

Next, subtract and we find that our discriminant is 0.

*Additional Info: Since the discriminant is zero, this means that this quadratic equation has 1 real solution.

4 0
3 years ago
Help pls!! Which of the following most specifically describes quadrilateral QUAD?
xxTIMURxx [149]

Answer:

I mean I think they are all quadrilateral, but the one that is congruent and perpendicular on both sides is a square.

Step-by-step explanation:

6 0
3 years ago
Prove that 6(n+6)-(2n+3) is odd number for all n£N​
Mice21 [21]

Answer:

\begin{aligned}6(n+6)-(2n+3) & = 6n+36-2n-3\\& = 4n+33\\& = 4n + 32 + 1\\& = 2(2n+16) + 1\end{aligned}

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If 2(2n + 16) is even, then adding 1 to this makes it odd.

Thus proving that the given expression is an odd number for all n \in \mathbb{N}

4 0
2 years ago
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