Answer:
In sub procedure or normal program?
Answer:
We can achieve this by using cURL command and GET command.
Explanation:
<u>cURL command:
</u>
- cURL command is the command of the command line tools which are available on the following platforms such as Linux, Windows, Mac OS, and many other Operating Systems.
- From the servers, cURL transfer the following data by using any of the protocol which are supported such as SFTP, HTTPS, HTTP, FTPS or many of the other protocols.
<u>
</u>
<u>GET command:
</u>
GET command is the function by which from the particular URL we can retrieve the resources.
Alternative 1:A small D-cache with a hit rate of 94% and a hit access time of 1 cycle (assume that no additional cycles on top of the baseline CPI are added to the execution on a cache hit in this case).Alternative 2: A larger D-cache with a hit rate of 98% and the hit access time of 2 cycles (assume that every memory instruction that hits into the cache adds one additional cycle on top of the baseline CPI). a)[10%] Estimate the CPI metric for both of these designs and determine which of these two designsprovides better performance. Explain your answers!CPI = # Cycles / # InsnLet X = # InsnCPI = # Cycles / XAlternative 1:# Cycles = 0.50*X*2 + 0.50*X(0.94*2 + 0.06*150)CPI= 0.50*X*2 + 0.50*X(0.94*2 + 0.06*150) / X1= X(0.50*2 + 0.50(0.94*2 + 0.06*150) ) / X= 0.50*2 + 0.50(0.94*2 + 0.06*150)= 6.44Alternative 2:# Cycles = 0.50*X*2 + 0.50*X(0.98*(2+1) + 0.02*150)CPI= 0.50*X*2 + 0.50*X(0.98*(2+1) + 0.02*150) / X2= X(0.50*2 + 0.50(0.98*(2+1) + 0.02*150)) / X= 0.50*2 + 0.50(0.98*(2+1) + 0.02*150)= 3.97Alternative 2 has a lower CPI, therefore Alternative 2 provides better performance.
Answer:
<em>C++.</em>
#include <iostream>
using namespace std;
////////////////////////////////////////////////////////////////
int main() {
int weekly_hours = 0;
int hourly_rate;
float gross_pay = 0;
cout<<"Enter weekly hours worked: ";
cin>>weekly_hours;
cout<<"Enter hourly rate: ";
cin>>hourly_rate;
cout<<endl;
////////////////////////////////////////////////
if (weekly_hours > 40) {
gross_pay = (weekly_hours*hourly_rate) + ((weekly_hours*hourly_rate)*0.5);
}
else
gross_pay = weekly_hours*hourly_rate;
cout<<"Weekly gross pay: $"<<gross_pay;
////////////////////////////////////////////////
return 0;
}
