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Scilla [17]
3 years ago
5

When breaking a problem down, you often encounter elements that you want to use repeatedly in your code. Sometimes it's appropri

ate to write a new function; at other times it's appropriate to write a loop. There is no hard-and-fast rule as to which is better, but what do you think? What kinds of circumstances would lead you to writing a function versus using a loop?
Computers and Technology
1 answer:
ddd [48]3 years ago
8 0

<u>Answer:</u>

<em>FUNCTION:</em>

  • A function does not require the number of times that the <em>code script needs to be executed </em>
  • When we go for large programming, ie. while creating projects, we can invoke function from one file to another based on the access <em>specifier mentioned for the function. </em>
  • There is a stack call created in the memory whenever a <em>function is called. </em>

<em>LOOP :</em>

  • Whereas the number of times that the loop has to be <em>executed must be defined </em>
  • A loop cannot be called, it can be used only the code block in <em>which it is present. </em>
  • There is not overhead of creating a stack since it is not invoked and there is no <em>transfer of control from one module to another </em>

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Answer:

while True:

   number = int(input("Enter a number: "))

   product = number * 10

   if product > 100:

       break

print(str(product))

Explanation:

Create a while loop that iterates until a specific condition is created inside

Ask the user for the input

Multiply the input and put the result in product

Check if the product is greater than 100. If it is, stop the loop using break keyword

When the loop is done, print the product

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Illustrate that the system is in a safe state by demonstrating an order in which the threads may complete.If a request from thre
Kamila [148]

Answer:

a. safe sequence is T2 , T3, T0, T1, T4.

b. As request(T4) = Available, so the request can be granted immediately

c. As request(T2) < Available, so the request can be granted immediately

d. As request(T3) < Available, so the request can be granted immediately.

Explanation:

It will require matrix

[i, j] = Max [i, j] – Allocation [i, j]

A B C D

T0 3 3 3 2

T1 2 1 3 0

T2 0 1 2 0

T3 2 2 2 2

T4 3 4 5 4

Available = (2 2 2 4)

1. Need(T2) < Available so, T2 can take all resources

Available = (2 2 2 4) + (2 4 1 3) (Allocation of T2) = (4 6 3 7)

2. Need(T3)<Available so, T3 will go next

Available = (4 6 3 7) + (4 1 1 0) = (8 7 4 7)

Like wise next T0, T1, T4 will get resources.

So safe sequence is T2 , T3, T0, T1, T4.

(Note, there may be more than one safe sequence).

Solution b.

Request from T4 is (2 2 2 4) and Available is (2 2 2 4)

As request(T4) = Available, so the request can be granted immediately.

Solution c.

Request from T2 is (0 1 1 0) and Available is (2 2 2 4)

As request(T2) < Available, so the request can be granted immediately.

Solution d.

Request from T3 is (2 2 1 2) and Available is (2 2 2 4)

As request(T3) < Available, so the request can be granted immediately.

5 0
3 years ago
I need help please and thank you
Evgen [1.6K]

Answer:

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For "WORST way to handle the situation," Option 4 would be the best because you're basically just hanging up on the person.

5 0
3 years ago
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