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Scilla [17]
4 years ago
5

When breaking a problem down, you often encounter elements that you want to use repeatedly in your code. Sometimes it's appropri

ate to write a new function; at other times it's appropriate to write a loop. There is no hard-and-fast rule as to which is better, but what do you think? What kinds of circumstances would lead you to writing a function versus using a loop?
Computers and Technology
1 answer:
ddd [48]4 years ago
8 0

<u>Answer:</u>

<em>FUNCTION:</em>

  • A function does not require the number of times that the <em>code script needs to be executed </em>
  • When we go for large programming, ie. while creating projects, we can invoke function from one file to another based on the access <em>specifier mentioned for the function. </em>
  • There is a stack call created in the memory whenever a <em>function is called. </em>

<em>LOOP :</em>

  • Whereas the number of times that the loop has to be <em>executed must be defined </em>
  • A loop cannot be called, it can be used only the code block in <em>which it is present. </em>
  • There is not overhead of creating a stack since it is not invoked and there is no <em>transfer of control from one module to another </em>

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Write a C program that reads two hexadecimal values from the keyboard and then stores the two values into two variables of type
sattari [20]

Solution :

#include  $$

#include $$

#include $$

//Converts $\text{hex string}$ to binary string.

$\text{char}$ * hexadecimal$\text{To}$Binary(char* hexdec)

{

 

long $\text{int i}$ = 0;

char *string = $(\text{char}^ *) \ \text{malloc}$(sizeof(char) * 9);

while (hexdec[i]) {

//Simply assign binary string for each hex char.

switch (hexdec[i]) {

$\text{case '0'}:$

strcat(string, "0000");

break;

$\text{case '1'}:$

strcat(string, "0001");

break;

$\text{case '2'}:$

strcat(string, "0010");

break;

$\text{case '3'}:$

strcat(string, "0011");

break;

$\text{case '4'}:$

strcat(string, "0100");

break;

$\text{case '5'}:$

strcat(string, "0101");

break;

$\text{case '6'}:$

strcat(string, "0110");

break;

$\text{case '7'}:$

strcat(string, "0111");

break;

$\text{case '8'}:$

strcat(string, "1000");

break;

$\text{case '9'}:$

strcat(string, "1001");

break;

case 'A':

case 'a':

strcat(string, "1010");

break;

case 'B':

case 'b':

strcat(string, "1011");

break;

case 'C':

case 'c':

strcat(string, "1100");

break;

case 'D':

case 'd':

strcat(string, "1101");

break;

case 'E':

case 'e':

strcat(string, "1110");

break;

case 'F':

case 'f':

strcat(string, "1111");

break;

default:

printf("\nInvalid hexadecimal digit %c",

hexdec[i]);

string="-1" ;

}

i++;

}

return string;

}

 

int main()

{ //Take 2 strings

char *str1 =hexadecimalToBinary("FA") ;

char *str2 =hexadecimalToBinary("12") ;

//Input 2 numbers p and n.

int p,n;

scanf("%d",&p);

scanf("%d",&n);

//keep j as length of str2

int j=strlen(str2),i;

//Now replace n digits after p of str1

for(i=0;i<n;i++){

str1[p+i]=str2[j-1-i];

}

//Now, i have used c library strtol

long ans = strtol(str1, NULL, 2);

//print result.

printf("%lx",ans);

return 0;

}

4 0
3 years ago
The browser feature which enables tabs to work independently from one another so if one crashes, the others may continue to work
Mars2501 [29]

Answer:

Tab isolation

Explanation:

Tab isolation is a feature of the browser that works to protect your data from malware. its uses to enhance the reliability of the browser by considering the impact of the crash.

A browser without the tab isolation can be crash fully due to the crashing of one tab. this feature helps to recover the previous opening tab after crashing while on the previous version of the browser if one tab crashes then it automatically crashes all other tabs.

8 0
3 years ago
Hi please help ASAP it's about html!​
uranmaximum [27]
<h2><u>Given</u> :-</h2>

Create a HTML code for writing a web page for your school time-table.

<h2><u>Answer</u> :-</h2>

<html>

<head>

<title> Time Table </title>

</head>

<hrcolor = "red">

<hrcolor = "blue">

<body>

<table><tr = "7"><md = "7"><Period 1_></table>

</body>

</html>

\\

Answered by - ItzMaster

7 0
3 years ago
Now, extend your test program by adding a second function named split that will identify all the individual values in a comma se
otez555 [7]

Answer:

The code to copy is :

#include <iostream>

#include <string>

using namespace std;

string nextString(string str, int start_index);

int split(string str, string a[], int max_size);

int main()

{

const int VALUES = 20;

string somestring;

string varray[VALUES];

//Prompt the user to enter a comma separated string

cout << "Enter a comma seperated string: ";

//read the string

getline(cin, somestring);

//call split() method on the given string and

//store the count of individual strings in cnt

int cnt = split(somestring, varray, VALUES);

//Print the individual strings

for (int i = 0; i<cnt; i++)

cout << varray[i] << endl;

return 0;

}

//returns a sub string that starts at strat_index

//in the given string and ends before a comma

string nextString(string str, int start_index)

{

int i;

//find a comma or end of the string, after strat_index

for (i = start_index;i < str.length();i++)

{

//if comma is found, exit the loop

if (str.at(i) == ',')

break;

}

//extract the sub string

string out= str.substr(start_index, i-start_index);

return out;

}

//splits the comma separted string as individual strings

//and returns the number of individual strings

int split(string str, string a[], int max_size)

{

int i, j;

int start_index = 0;

//search for commas in the given string

for (i = 0,j=0;i < str.length();i++)

{

//if comma is identified or end of the string is identified

//, then get a strig that starts at start_index using next string

if (str.at(i) == ',' ||i==str.length()-1)

{

//save each string into an array of strings

a[j] = nextString(str, start_index);

//update the next string starting postion(starts after comma)

start_index = i + 1;

j++;

}

}

return j;

Explanation:

Please see attachments

7 0
3 years ago
Complete the method definition to output the hours given minutes. Output for sample program:3.5import java.util.Scanner;public c
Aliun [14]

Answer:

import java.util.Scanner;

public class num1 {

   public static void outputMinutesAsHours(double origMinutes) {

       double hours = origMinutes / 60;

       System.out.println("The converted hours is " + hours);

   }

   public static void main(String[] args) {

       Scanner scnr = new Scanner(System.in);

       double minutes;

       minutes = scnr.nextDouble();

       outputMinutesAsHours(minutes); // Will be run with 210.0, 3600.0,

       System.out.println("");

   }

}

Explanation:

The question required us to only write the statement to complete the line

outputMinutesAsHours(double origMinutes) { /* Your solution goes here */ }

The solution double hours = origMinutes / 60; solves this because there are 60 minutes in one hour, so to conver minutes to hours, you divide the number of minutes by 60

8 0
3 years ago
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