Question

Formula1" title=" \frac{x + 1 }{2} = \frac{7x - 3}{2} " alt=" \frac{x + 1 }{2} = \frac{7x - 3}{2} " align="absmiddle" class="latex-formula">
Solve it ok please .​

Answer 1

Answer:

$x=\dfrac{2}{3}$

Step-by-step explanation:

Given equation:

$\dfrac{x+1}{2}=\dfrac{7x-3}{2}$

Step 1: Multiply both sides by $2$.

$\implies 2\left(\dfrac{x+1}{2}\right)=2\left(\dfrac{7x-3}{2}\right)$

$\implies x+1=7x-3$

Step 2: Subtract $7x$ from both sides.

$\implies x-7x+1=7x-7x-3$

$\implies -6x+1=-3$

Step 3: Subtract $1$ from both sides.

$\implies -6x+1-1=-3-1$

$\implies -6x=-4$

Step 4: Divide both sides by $-6$ and simplify.

$\implies \dfrac{-6x}{-6}=\dfrac{-4}{-6}$

$\implies x=\dfrac{4}{6}=\boxed{\dfrac{2}{3}}$

Answer 2

Answer:

$\sf x =\dfrac{2}{3}$

Explanation:

$\sf \rightarrow \dfrac{x+1}{2} = \dfrac{7x-3}{2}$

cross multiply

$\sf \rightarrow 2(x+1) = 2(7x-3)$

divide both sides by 2

$\sf \rightarrow x + 1 = 7x-3$

isolate variables

$\sf \rightarrow x -7x = -3-1$

simplify

$\sf \rightarrow -6x = -4$

divide both sides by -6

$\sf \rightarrow \dfrac{-6x}{-6} = \dfrac{-4}{-6}$

simplify

$\sf \rightarrow x =\dfrac{2}{3}$