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Minchanka [31]
1 year ago
12

Solve P=2G + 2M for G. G=

Mathematics
1 answer:
shusha [124]1 year ago
6 0

Answer:

G=\frac{P-2M}{2}

Step-by-step explanation:

P=2G+2M \\ \\ P-2M=2G \\ \\ G=\frac{P-2M}{2}

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Rainbow [258]

Answer:

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Step-by-step explanation:

17*8=136

6 0
3 years ago
Place the following in order: 0.03, 6%, 1/50, 0.12, and 1/25
Lina20 [59]

Answer: 100

Step-by-step explanation:

8 0
3 years ago
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At the skateboard park, the hot new attraction is the U-Dip, a cement structure embedded into the ground. The cross-sectional vi
Ratling [72]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
Molly was on a long 136 mile road trip. The first part of the trip there was lots of traffic, she only averaged 16 mph. The seco
Mazyrski [523]

Answer:

In traffic, she drove for 3 hours

and After the traffic cleared she drove for 2 hours.

Explanation:

Given that the road trip was 136 miles;

d=136

The first part of the trip there was lots of traffic, she only averaged 16 mph;

v_1=16

The second part of the trip there was no traffic so she could drive 44 mph;

v_2=44

She traveled for a total of 5 hours;

t=5

let x represent the time in traffic when she traveled at 16 mph

t_1=x

the time the traffic is clear would be;

t_2=t-t_1=5-x

Recall that distance equals speed multiply by time;

d=v_1t_1_{}_{}^{}+v_2t_2

substituting the values;

136=16x+44(5-x)

solving for x;

\begin{gathered} 136=16x+220-44x \\ 44x-16x=220-136 \\ 28x=84 \\ x=\frac{84}{28} \\ x=3 \end{gathered}

So;

\begin{gathered} t_1=3\text{ hours} \\ t_2=5-x=5-3=2 \\ t_2=2\text{ hours} \end{gathered}

Therefore, In traffic, she drove for 3 hours

and After the traffic cleared she drove for 2 hours.

7 0
1 year ago
A function f defined by f(x) = x² + px + q is such that f(3) = 6 and f¹(3) = 0. Find the value of q.
CaHeK987 [17]

Answer:

q = 15

Step-by-step explanation:

Given

f(x) = x² + px + q , then

f(3) = 3² + 3p + q = 6 , that is

9 + 3p + q = 6 ( subtract 9 from both sides )

3p + q = - 3 → (1)

---------------------------------------

f'(x) = 2x + p , then

f'(3) = 2(3) + p = 0, that is

6 + p = 0 ( subtract 6 from both sides )

p = - 6

Substitute p = - 6 into (1)

3(- 6) + q = - 3

- 18 + q = - 3 ( add 18 to both sides )

q = 15

5 0
3 years ago
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