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zavuch27 [327]
3 years ago
6

PLSPLS HELP ME ILL GIVE BRAINLIEST

Mathematics
1 answer:
alexandr1967 [171]3 years ago
6 0

Answer:

b

Step-by-step explanation:

there is no steady slope so itd have to be b

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Four children have small toys. The first child has 1/10 of the toys, the second child has 12 more toys than the first, the third
GREYUIT [131]
Let the total toys be x.

The first has (1/10)x =  x/10


The third child has one more toys than the first =  x/10  + 1

The fourth has double of the third:  =  2* (x/10 + 1)  =  2x/10 + 2


Since we know that the second child has 12 more toys than the first

Therefore the Second  minus First = 12.


First let us find the second.

1st + 2nd + 3rd + 4th = x

x/10   +  2nd +  (x/10 + 1) + (2x/10 + 2) = x

2nd + x/10  + x/10 + 1 + 2x/10 + 2 = x

2nd + x/10 + x/10 + 2x/10 + 1 + 2  = x

2nd + 4x/10 + 3 = x

2nd = x - 4x/10 - 3

2nd =  6x/10  - 3

But recall

2nd - 1st = 12

6x/10 - 3 - x/10 = 12

6x/10 - x/10 = 12 + 3

5x/10 = 15

5x =  15 * 10

x  = 15*10 /5

x = 30

So there were 30 toys in all.
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3 years ago
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