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sasho [114]
1 year ago
5

Urve revolves around the x-axis. if you cannot evaluate the integral exactly, use your calculator to approximate it. (round your

answer to four decimal places. ) y = 16 − x2 from x = −1 to x = 1
Mathematics
1 answer:
Archy [21]1 year ago
4 0

The value of integration of y=16-x^{2} from x=-1 to x=1 is 94/3.

Given the equation y=16-x^{2} and the limit of the integral be x=-1,x=1.

We are required to find the value of integration of y=16-x^{2} from x=-1 to x=1.

Equation is relationship between two or more variables that are expressed in equal to form.Equation of two variables look like ax+by=c.It may be linear equation, quadratic equation, or many more depending on the power of variable.

Integration is basically opposite of differentiation.

y=16-x^{2}

Find the integration of 16-x^{2}.

=16x-x^{3}/3

Now find the value of integration from x=-1 to x=1.

=16(1)-(1)^{3}/3-16(-1)-(-1)^{3}/3

=16(1)-1/3+16-1/3

=32-2/3

=(96-2)/3

=94/3

Hence the value of integration of y=16-x^{2} from x=-1 to x=1 is 94/3.

Learn more about integration at brainly.com/question/27419605

#SPJ4

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The standard form of a quadratic equation is \displaystyle{ y=ax^2+bx+c, while the vertex form is:

                      y=a(x-h)^2+k, where (h, k) is the vertex of the parabola.

What we want is to write \displaystyle{ y=3x^2-18x-6 as y=a(x-h)^2+k

First, we note that all the three terms have a factor of 3, so we factorize it and write:

\displaystyle{ y=3(x^2-6x-2).


Second, we notice that x^2-6x are the terms produced by (x-3)^2=x^2-6x+9, without the 9. So we can write:

x^2-6x=(x-3)^2-9, and substituting in \displaystyle{ y=3(x^2-6x-2) we have:

\displaystyle{ y=3(x^2-6x-2)=3[(x-3)^2-9-2]=3[(x-3)^2-11].

Finally, distributing 3 over the two terms in the brackets we have:

y=3[x-3]^2-33.


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A cuboid with a volume of 924cm^3 has dimensions 4cm, (x+1)cm and (x+11). Show clearly that x^2+12x-220=0 solve the equation by
garik1379 [7]

Answer:

x^2+12x-220=0 -- Proved

x = 10\ \ \ x = -22

Step-by-step explanation:

Given

Volume = 924cm^3

Dimension: 4cm; (x+1)cm; (x+11)cm

Required

Show that x^2+12x-220=0

The volume is calculated as:

4 * (x + 1) * (x + 11) = 924

Open the brackets

(4x + 4) * (x + 11) = 924

4x^2 + 44x + 4x + 44 = 924

4x^2 + 48x+ 44 = 924

Collect Like Terms

4x^2 + 48x+ 44 - 924=0

4x^2 + 48x -880=0

Divide through by 4

\frac{4x^2}{4} + \frac{48x}{4} -\frac{880}{4}=0

x^2+12x-220=0

Solving further:

Expand the expression

x^2 + 22x - 10x - 220 = 0

Factorize:

x(x + 22) - 10(x + 22) = 0

(x - 10)(x + 22) = 0

Split:

x - 10 = 0;\ \ \ x + 22 = 0

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find two consecutive odd integers whose product is 1 less than 6 times their sum. Domain for the smallest : {-1, 1, 11}
inn [45]
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Solve this quadratic expression:

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x' = [10 + √144]/2      and  x" = [10 - √64]/2

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x = 11 and x = -1

We have 2 solutions that satisfy the problem:

1st for x = 11, the numbers at 11 and 13
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you will find that both generates an equlity


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