Question

Urve revolves around the x-axis. if you cannot evaluate the integral exactly, use your calculator to approximate it. (round your answer to four decimal places. ) y = 16 − x2 from x = −1 to x = 1

Answer 1

The value of integration of y=16-$x^{2}$ from x=-1 to x=1 is 94/3.

Given the equation y=16-$x^{2}$ and the limit of the integral be x=-1,x=1.

We are required to find the value of integration of y=16-$x^{2}$ from x=-1 to x=1.

Equation is relationship between two or more variables that are expressed in equal to form.Equation of two variables look like ax+by=c.It may be linear equation, quadratic equation, or many more depending on the power of variable.

Integration is basically opposite of differentiation.

y=16-$x^{2}$

Find the integration of 16-$x^{2}$.

=16x-$x^{3}/3$

Now find the value of integration from x=-1 to x=1.

=16(1)-$(1)^{3}/3$-16(-1)-$(-1)^{3}/3$

=16(1)-1/3+16-1/3

=32-2/3

=(96-2)/3

=94/3

Hence the value of integration of y=16-$x^{2}$ from x=-1 to x=1 is 94/3.

Learn more about integration at brainly.com/question/27419605

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