12s - 20 < 3s - 25 |+20
12s < 3s - 5 |-3s
9s < -5 |:9
s < -5/9
Answer: Any number from the set (-∞, -5/9).
The maximum height the ball achieves before landing is 682.276 meters at t = 0.
<h3>What are maxima and minima?</h3>
Maxima and minima of a function are the extreme within the range, in other words, the maximum value of a function at a certain point is called maxima and the minimum value of a function at a certain point is called minima.
We have a function:
h(t) = -4.9t² + 682.276
Which represents the ball's height h at time t seconds.
To find the maximum height first find the first derivative of the function and equate it to zero
h'(t) = -9.8t = 0
t = 0
Find second derivative:
h''(t) = -9.8
At t = 0; h''(0) < 0 which means at t = 0 the function will be maximum.
Maximum height at t = 0:
h(0) = 682.276 meters
Thus, the maximum height the ball achieves before landing is 682.276 meters at t = 0.
Learn more about the maxima and minima here:
brainly.com/question/6422517
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B. 7
49 divided by 7 is 7.
Answer:
264
Step-by-step explanation:
because 33 is 11 times 3 so you multiply the 24x11 equal 264
33/264
