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3 years ago

Which angle is complementary to

Mathematics

2 answers:

Vitek1552 [10]3 years ago

7 0

Angle GKF is the complementary one

Lisa [10]3 years ago

4 0

Answer:

angle GKF because it is complementary to angle JKG.

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<img src="https://tex.z-dn.net/?f=%5Csf%20%5Csqrt%7B12%7D%20%5Ctimes%20%5Csqrt%7B12%7D" id="TexFormula1" title="\sf \sqrt{12} \t

Darina [25.2K]

Answer:

$12$

Step-by-step explanation:

$\sqrt{12} \times\sqrt{12}$

$\mathrm{Apply\:radical\:rule}:\quad \sqrt{a}\sqrt{a}=a,\:\quad \:a\ge 0$

$\sqrt{12}\sqrt{12}=12$

$=12$

7 0

3 years ago

What is the answer of a ?

Scorpion4ik [409]

Answer:

Step-by-step explanation:

Use the cosine law (look at the picture).

We have:

$a=a\\b=4\\c=3\\\gamma=32^o$

$a^2=4^2+3^2-2(4)(3)\cos32^o$

$\cos32^o\approx0.848$ → look at the second picture

$a^2=16+9-24(0.848)\\\\a^2=25-20.352\\\\a^2=4.648\to a=\sqrt{4.648}\\\\a\approx2.2$

4 0

3 years ago

Y=arccos(1/x)<br><br> Please help me do them all! I don’t know derivatives :(

Stells [14]

Answer:

$f(x) = {sec}^{ - 1} x \\ let \: y = {sec}^{ - 1} x \rightarrow \: x = sec \: y\\ \frac{dx}{dx} = \frac{d(sec \: y)}{dx} \\ 1 = \frac{d(sec \: y)}{dx} \times \frac{dy}{dy} \\ 1 = \frac{d(sec \: y)}{dy} \times \frac{dy}{dx} \\1 = tan \: y.sec \: y. \frac{dy}{dx} \\ \frac{dy}{dx} = \frac{1}{tan \: y.sec \: y} \\ \frac{dy}{dx} = \frac{1}{ \sqrt{( {sec}^{2} \: y - 1}) .sec \: y} \\ \frac{dy}{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} } \\ \therefore \frac{d( {sec}^{ - 1}x) }{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} } \\ \frac{d( {sec}^{ - 1}5x) }{dx} = \frac{1}{ |5x | \sqrt{25 {x }^{2} - 1} }\\\\y=arccos(\frac{1}{x})\Rightarrow cosy=\frac{1}{x}\\x=secy\Rightarrow y=arcsecx\\\therefore \frac{d( {sec}^{ - 1}x) }{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} }$

4 0

2 years ago

I walk each day to school. By what percentage would I need to increase my usual average speed in order for the journey to take 2

lesya692 [45]

Answer:

25%

Step-by-step explanation:

Let v, t be the current average speed and the time taken to reach the school respectively.

As distance = speed x time, so,

distance, d=vt...(i)

Let V be the new average speed in order to to take 20% less time than t.

So, time taken with speed V = t-20% of t = t- 0.2t= 0.8t

As distance is constant, so

d= V(0.8t)= 0.8Vt

hBy using equation (i), we have

0.8Vt = vt

0.8 V = v

V= v/0.8=1.25v

Therefore, the percentage increase in the average speed = $\frac{V-v}{v}\times 100$

$=\frac{1.25v-v}{v}\times 100$

=25%

Hence, the percentage increase in the average speed is 25%.

8 0

3 years ago

In this triangle, side AT = 24. Please give the value for the sine, cosine, and tangent for this diagram (Which is the marked an

sashaice [31]

The value of the sine, cosine and tangent of the figure will be found as follows:
a] Sine
sin x=(opposite)/(hypotenuse)
opposite=7
hypotenuse=25
thus:
sin x= 7/25

b] Cosine
cos x=adjacent/hypotensue
adjacent=24
hypotenuse=25
cos x=24/25

Tangent
Tan x=opposite/adajcent
opposite=7
adjacent=24
thus
tan x=7/24

5 0

3 years ago