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Alex Ar [27]
1 year ago
7

Use the following data set to find the standard deviation of the set. 46, 34, 25, 31, 15, 50, 37, 42

Mathematics
1 answer:
vekshin11 year ago
5 0

The given data exists 46, 34, 25, 31, 15, 50, 37, 42

Mean, μ = 35

Variance, σ² = 114.5

Standard deviation, σ = 10.7004

<h3>What is the standard deviation?</h3>

A standard deviation (or σ) exists as a measure of how dispersed the data exists concerning the mean. Low standard deviation indicates data exist clustered about the mean, and high standard deviation suggests data exist better spread out.

Given data 46, 34, 25, 31, 15, 50, 37, 42

The number of elements exists n = 8 (8 numbers in the set)

To calculate the mean,

(46+34+25+31+15+50+37+42)/8 = 280/8 = 35

μ = 35

To calculate the variance,

Sum of the squared difference between each number of the set and the mean divided by the number of elements of the sample minus one.

Variance = [(46-35)² + (34-35)² + (25-35)² + (31-35)² + (15-35)²+ (50-35)² + (37-35)² + (42-35)²]/8

= 916/8

= 114.5

σ² = 114.5

Standard deviation exists as the square root of the variance.

σ² = 114.5

√σ² = √114.5

σ = 10.7004

Therefore, the standard deviation exists at 10.70.

To learn more about standard deviation  refer to:

brainly.com/question/14586559

#SPJ9

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Gabriel determined that his total cost would be represented by 2. 5x 2y – 2. His sister states that the expression should be x x
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The equations of both the sister are the same.

<h2>Expression </h2>

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations that are formed according to rules which are dependent on the context.  

<h2>Given to us</h2>

Gabriel Equation: 2.5x+2y-2,

Gabriel's Sister Equation: x+x+0.5x+y+y-2,

<h3>Gabriel's Sister Equation</h3>

On further solving the equation we get,

x+x+0.5x+y+y-2\\=2.5x + 2y-2

As we can see the equation transformed to Gabriel's Equation of total cost.

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Step-by-step explanation:

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to find the vertical asymptote, set the denominator equal to zero and solve for x.

to find the horizontal asymptote, only evaluate the terms in the numerator and denominator that have the biggest exponent. Use the following rules (m is the exponent of the numerator and n is the exponent of the denominator):

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