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wolverine [178]
3 years ago
9

What would be after650 what would be 6.5

Mathematics
1 answer:
trapecia [35]3 years ago
3 0

Answer:

this doesn't make sense

Step-by-step explanation:

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Find the slope of the line that contains (6,-4) and (-4,-4)
frez [133]

Answer:y = -4

Step-by-step explanation: In order to find the slope by these two points, (6,-4), and (-4,-4), you must use the slope formula:

rise/run, which is this case, is y2-y1 / x2 - x1 <--- this is the slope formula

Let 6 be x2, -4 be x1, y2 be -4, and y1 being -4, plug these numbers in.

-4-(-4) / 6- (-4)

-4 + 4/ 6 +4

0/10 The slope of the line is zero, with a y-axis at -4. We know this because there is a zero in the final result and the y- coordinate between (6,-4) and (-4,-4) do not change in the slightest.

The final answer is then y = -4

5 0
3 years ago
What is r ÷ p equal to?
marshall27 [118]

Answer:

if those are variables they can equal anything you want like r=4 and p=2 r/p = 2

Step-by-step explanation:

7 0
3 years ago
If A=p+prt, than t equalls?
ella [17]

Answer:

\boxed{t=\frac{A-p}{pr}}

Step-by-step explanation:

A=p+prt

Subtract p on both sides.

A-p=p+prt-p

A-p=prt

Divide both sides by pr.

\displaystyle \frac{A-p}{pr} =\frac{prt}{pr}

\displaystyle{\frac{A-p}{pr} =t}

5 0
3 years ago
Read 2 more answers
HELP DUE IN 5 MINS!<br><br> x=??<br><br> y=??
vodka [1.7K]

Answer:

x = 55

y = 45

Step-by-step explanation:

In similar triangles, the ratio between similar sides are the same. So,

AB/ED = BC/EF = AC/DF

Substitute values that they give

6/15 = 18/y = 22/x

Solve 6/15 = 18/y by cross-multiplying

6y = 15*18 = 324

Divide both sides by 6

y= 45

Solve 6/15 = 22/x by cross-multiplying.

6x = 22*15 = 330

Divide both sides by 6.

x = 55

Because there is some dispute between the answers, let's check the ratios.

6/15 = 18/45 = 22/55

0.4 = 0.4 = 0.4

True, x = 55 and y=45

4 0
3 years ago
Read 2 more answers
Explain how System 1 becomes equivalent to System 2.
LenKa [72]

Answer:

In the procedure

Step-by-step explanation:

we have

<em>System 1</em>

Ax+By=C -----> equation A

Lx+My=N -----> equation B

<em>step 1</em>

Multiply equation B by -1 both sides

(-1)*(Lx+My=)N*(-1)

-Lx-My=-N ------> equation C

<em>step 2</em>

Adds equation A and equation C

Ax+By=C

-Lx-My=-N

----------------

Ax-Lx+By-My=C-N

(A-L)x+(B-M)y=C-N -----> equation D

step 3

An equivalent system (System 2) is formed with

Ax+By=C -----> equation A

(A-L)x+(B-M)y=C-N -----> equation D

6 0
3 years ago
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