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2 years ago

Jaden uses the net below to design a box how much cardboard will Jw need to make the box

1 answer:

7 0

IfIf Jaden uses the net below to design a box. The number of cardboard will Jw need to make the box is: 128 ft².

<h3>Numbers of cardboard</h3>

First step is to find the Area of rectangle

Area of rectangle=6×4

Area of rectangle= 24ft²

Second step is to determine the numbers of cardboard using this formula

Numbers of cardboard=Total area of the rectangle+Total area of the square

Let plug in the formula

Numbers of cardboard= 4×24+16×2

Numbers of cardboard= 96 ft²+ 32ft²

Numbers of cardboard= 128 ft²

The complete question is:

Jayden uses the net below to design a box. A net with 4 rectangles and 2 squares. The rectangles measure 6 feet by 4 feet and the squares have side lengths of 4 feet. How much cardboard will Jayden need to make the box? A. 60 ft2 B. 96 ft2 C. 128 ft2 D. 144 ft2

Therefore If Jaden uses the net below to design a box. The number of cardboard will Jw need to make the box is:128 ft².

Learn more about Numbers of cardboard here:brainly.com/question/9581268

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A closed cylindrical vessel contains a fluid at a 5MPa pressure. The cylinder, which has an outside diameter of 2500mm and a wal

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Answer:

1) Increase in the diameter equals 3.5 mm

2) Increase in the length equals $0.0003724L_{i}$ where $L_{i}$ is the initial length of the vessel.

Step-by-step explanation:

The diametric strain in the vessel is given by

$\epsilon_{D} =\epsilon_{diam}-\nu \epsilon _{axial}$

We have

$\epsilon _{diam}=\frac{\sigma _{hoop}}{E}\\\\\sigma _{hoop}=\frac{\Delta P\times D}{2t}\\\\\therefore \epsilon _{diam}=\frac{\Delta P\times D}{2t\times E}$

Applying values we get

$\therefore \epsilon _{diam}=\frac{5\times 10^{6}\times 2.5}{2\times 20\times 10^{-3}\times 193\times 10^{9}}\\\\\therefore \epsilon _{diam}=\frac{5}{3088}$

Similarly axial strain is given by

$\epsilon _{diam}=\frac{\sigma _{axial}}{E}$

$\sigma _{axial}=\frac{\Delta P\times D}{4t}\\\\\therefore \epsilon _{axial}=\frac{\Delta P\times D}{4t\times E}$

Applying values we get

$\therefore \epsilon _{axial}=\frac{5\times 10^{6}\times 2.5}{4\times 20\times 10^{-3}\times 193\times 10^{9}}\\\\\therefore \epsilon _{diam}=\frac{2.5}{3088}$

Hence The effect of axial strain along the diameter is given by

$-\nu \epsilon _{axial}$

Applying values we get

$-\nu \epsilon _{axial}=-0.27\times \frac{2.5}{3088}=-0.0002185$

hence

$\epsilon _{D} =\frac{5}{3088}-0.0002185\\\\\epsilon =0.00140$

Now by definition of strain we have

$\epsilon _{D} =\frac{D_{f}-D_{i}}{D_{i}}\\\\\therefore D_{f}=D_{i}+\epsilon D_{i}\\\\D_{f}=2.5+0.0014\times 2.5\\\\\therefore D_{f}=2503.5mm$

Increase in the diameter is thus 3.5 mm

Using the same procedure for axial strain we have

$\epsilon_{axial} =\epsilon_{axial}-\nu \epsilon _{diam}$

Applying values we get

$\epsilon_{axial} =\frac{2.5}{3088}-0.27\times \frac{5}{3088}$

$\epsilon_{axial} =0.0003724$

Now by definition of strain we have

$\epsilon _{axial} =\frac{L_{f}-L_{i}}{L_{i}}\\\\\therefore \Delta L=0.0003724L_{i}$

where $L_{i}$ is the initial length of the cylinder.

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4 years ago

Xavier older brother has 568 songs on his music player. To the nearest hundred, about how many songs are on the music player?

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600 songs. Rounded to the nearest hundred.

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You are playing a board game and you have to pay $50 then you win $200 after that you have to pay $800 write an expression that

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Answer:

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Step-by-step explanation:

You have to pay $50

This is a negative to your account: -$50

You win $200

This is a positive to your account: + $200

After you have to pay $800

This is a negative to your account: - $800

Total transaction

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The expression that represent the situation is:

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3 years ago

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Answer:

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The required arrangements of tables is

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Step-by-step explanation:

Formula for unit rate :

$m=\dfrac{y_2-y_1}{x_2-x_1}$

From the given graph it is clear that the line passes through the points (0,0) and (11,20). So, unit rat of graph is

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The required arrangement of tables is

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To have infinite solutions, they have to be th esame line

match waht we do know

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