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Free_Kalibri [48]
4 years ago
15

In the pair of equations bx-6y=18 and 2x-3y=9, b is a whole number. The system of two equations has infinitely many solutions. W

hat is the value of b
Mathematics
2 answers:
statuscvo [17]4 years ago
8 0
To have infinite solutions, they have to be th esame line

match waht we do know

bx-6y=18
the coefient of y is -6
other one is
2x-3y=9
-3 times 2=-6
times 2nd equation by 2
4x-6y=18
bx-6y=18
b=4
exis [7]4 years ago
5 0
The value of b would be 4
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What is vertex of x^2+5x-3
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\text{The vertex of}\ ax^2+bx+c:\\\\(h,\ k),\ \text{where}\ h=\dfrac{-b}{2a};\ k=f(h)=\dfrac{-(-b^2-4ac)}{4a}

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3 years ago
A rectangle has a height of 6k3 and a width of 2k2 + 4k +5.
Trava [24]

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5 0
4 years ago
Pre algebra help ( will give brainliest ) sorry if it's hard to see
valentinak56 [21]
It would have changed by 1/3 is ur answer
4 0
4 years ago
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Find the distance between the points of intersection of the graphs of the functions.
Viefleur [7K]

Answer:

Find the value of x and y in coordinate form, that'll be the point of intersection.

Question 1

{ \rm{y =  {x}^{2} - 3x + 4 }} \\ { \boxed{ \tt{but \: y = x + 1 \: }}} \\  \\ { \rm{(x + 1) =  {x}^{2} - 3x + 4 }} \\  \\ { \rm{ {x}^{2} - 4x + 3 = 0 }} \\  \\ { \rm{(x - 3)(x - 1) = 0}} \\  \\ { \boxed{ \rm{x_{1} = 3 \:  \: and \:  \: x _{2}  = 1}}} \\  \\ { \boxed{ \tt{remember \: y = x + 1}}} \\  \\ { \rm{y _{1} = 4 \:  \: and \:  \: y _{2}  = 2 }}

Therefore, points of intersection are two

Answer: <u> </u><u>(</u><u>3</u><u>,</u><u> </u><u>4</u><u>)</u><u> </u><u>and</u><u> </u><u>(</u><u>1</u><u>,</u><u> </u><u>2</u><u>)</u>

Question 2:

Following the steps as in question 1

{ \rm{y =  {x}^{2}  - 4}} \\  \\{ \rm{2x - 4 =  {x}^{2}  - 4}} \\  \\ { \rm{ {x}^{2} = 2x }} \\  \\ { \boxed{ \rm{x = 2}}} \\ { \tt{remember : \: y = 2x - 4 }} \\ { \boxed{ \rm{y = 0}}}

Answer: <u>(2, 0)</u>

7 0
3 years ago
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