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kozerog [31]
3 years ago
12

The table below shows the scores on a math test.

Mathematics
2 answers:
Nastasia [14]3 years ago
5 0
With the use of a calculator with statistical functions, the standard deviation was found to be 12.54
svet-max [94.6K]3 years ago
3 0

Answer:

1572.5  

Step-by-step explanation:

David : 75  

Aaron : 75  

Ashley : 60  

Gina : 75  

Andrew : 75  

Kei : 95  

Monica : 100  

Anna : 60  

Lucas : 75  

Jennifer : 65

First calculate the mean  

Mean = \frac{\text{Sum of all observations}}{\text{Total no. of observations}}

So, Mean = \frac{75+75+60+75+75+95+100+60+75+65}{10}

Mean = 75.5

Standard deviation = \sum (x_i-\mu)^2

So, Standard deviation = (75-75.5)^2+(75-75.5)^2+(60-75.5)^2+(75-75.5)^2+(75-75.5)^2+(95-75.5)^2+(100-75.5)^2+(60-75.5)^2+(75-75.5)^2+(65-75.5)^2

Standard deviation = 1572.5

Hence the standard deviation is 1572.5  

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a new machine with better technology produces 210 gel pens every 15 minutes what is the concept of the proportionality in the re
Helen [10]

Answer:

<em>p = 14t</em>

Step-by-step explanation:

y = kx

The rate k = 210 ÷ 15 = 14 gel pens per minute

"p" is number of pens, "t" is number of minutes

<em>p = 14t</em>

4 0
3 years ago
Which of the following are one dimensional and have infinite length
Alik [6]
I got the one that truck was coming up and
4 0
3 years ago
Help me with this Please.
sukhopar [10]
35
the ratio for the two is 5:7 and you want to find _:49. to get from 7 to 49 you multiply the 7 by 7. because you did that to one side you have to do the same to the other and multiply 5 by 7 which gives you 35
6 0
2 years ago
How to evaluate the limit
anzhelika [568]
\displaystyle\lim_{x\to2}\frac{x^2-x+6}{x+2}

Both the numerator and denominator are continuous at x=2, which means the quotient rule for limits applies:

\dfrac{\displaystyle\lim_{x\to2}(x^2-x+6)}{\displaystyle\lim_{x\to2}(x+2)}=\dfrac{2^2-2+6}{2+2}=\dfrac84=2

Perhaps you meant to write that x\to-2 instead? In that case, you would have

\displaystyle\lim_{x\to-2}\frac{x^2-x+6}{x+2}=\lim_{x\to-2}\frac{(x+2)(x-3)}{x+2}=\lim_{x\to-2}(x-3)=-2-3=-5
4 0
3 years ago
CS Algebra
CaHeK987 [17]

Answer:

Hope this helps :)

Step-by-step explanation:

8(x - 2) = 2x + 8

y+9 = -2(y + 1)

value of x in 8(x - 2) = 2x + 8

x=4

substitue

y+9=−2(y+1)

value of y y+9=−2(y+1)

y= - 11/3 or 3.66...

x=4

y=4 (I rounded 3.66)

4 0
3 years ago
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