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ExtremeBDS [4]
1 year ago
14

What volume of an hcl solution with a ph of 1.3 can be neutralized by one dose of milk of magnesia?

Chemistry
1 answer:
kvv77 [185]1 year ago
7 0

274 mL H3 O+ and fully neutralized

It will take one teaspoon of Mg(OH)2 to completely neutralize 2.00×10^2mL  of H3O+.

<h3>What is the purpose of milk of magnesia?</h3>
  • For a brief period of time, this medicine is used to relieve sporadic constipation.
  • It is an osmotic laxative, which means that it works by drawing water into the intestines, which aids in causing bowel movement.
<h3>What dosage of milk of magnesia is recommended for constipation?</h3>
  • Take Milk of Magnesia once day, preferably before bed, in divided doses, or as prescribed by a physician.
  • suggested dosage: 30 mL to 60 mL for adults and kids 12 years of age and older. 15 mL to 30 mL for children aged 6 to 11 years.

learn more about milk of magnesia here

brainly.com/question/15178597

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the question you are looking for is

People often take milk of magnesia to reduce the discomfort associated with acid stomach or heartburn. The recommended dose is 1 teaspoon, which contains 4.00x 10^{2} mg of Mg(OH)_2. What volume of an HCl solution with a pH of 1.3 can be neutralized by one dose of milk of magnesia? If the stomach contains 2.00x10^{2}mL of pH 1.3 solution, is all the acid neutralized? If not, what fraction is neutralized?

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A sample of gas occupies 17 mL at -122°C. What volume does the sample occupy at 70°C?
aev [14]

Answer: 38.6 ml

Explanation:

Charles' Law: This law states that volume is directly proportional to the temperature of the gas at constant pressure and number of moles.


V\propto T    (At constant pressure and number of moles)

\frac{V_1}{T_1}=\frac{V_2}{T_2}

V_1= initial volume = 17 ml

V_2= final volume = ?

T_1= initial temperature =-122^0C=273+(-122)=151K

T_2=final temperature=70^0C= 70+273=343K

\frac{17}{151}=\frac{V_2}{343}

V_2=38.6ml

Thus final volume is 38.6 ml at 70^0C




7 0
3 years ago
The radioisotope radon-222 has a half life of 3.8 days. How much of a 10 gram sample of radon-222 would be left after 15.2 days?
djyliett [7]

Answer:

0.625 g

Explanation:

Given data:

Half life of radon-222 = 3.8 days

Total mass of sample = 10 g

Mass left after 15.2 days = ?

Solution:

Number of half lives = T elapsed / Half life

Number of half lives = 15.2 / 3.8

Number of half lives = 4

At time zero = 10 g

At first half life = 10 g/2 = 5 g

At 2nd half life = 5 g/ 2= 2.5 g

At third half life = 2.5 g/2 = 1.25 g

At 4th half life = 1.25 g/2 = 0.625 g

4 0
3 years ago
2 Polnts
Marina CMI [18]

Answer:

In chemistry, a symbol is an abbreviation for a chemical element. Symbols for chemical elements normally consist of one or two letters from the Latin alphabet and are written with the first letter capitalised.

Earlier symbols for chemical elements stem from classical Latin and Greek vocabulary. For some elements, this is because the material was known in ancient times, while for others, the name is a more recent invention. For example, Pb is the symbol for lead (plumbum in Latin); Hg is the symbol for mercury (hydrargyrum in Greek); and He is the symbol for helium (a new Latin name) because helium was not known in ancient Roman times. Some symbols come from other sources, like W for tungsten (Wolfram in German) which was not known in Roman times.

Explanation:

7 0
3 years ago
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Which of the following is the correct name for Cr203?
algol13
It’s B. Chromium(III) oxide
4 0
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The nucleus of isotope A of an element has a larger mass than isotope B of the same elemen
konstantin123 [22]

Answer:

B

Explanation:

since isotopeA has bigger mass number

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