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ExtremeBDS [4]
1 year ago
14

What volume of an hcl solution with a ph of 1.3 can be neutralized by one dose of milk of magnesia?

Chemistry
1 answer:
kvv77 [185]1 year ago
7 0

274 mL H3 O+ and fully neutralized

It will take one teaspoon of Mg(OH)2 to completely neutralize 2.00×10^2mL  of H3O+.

<h3>What is the purpose of milk of magnesia?</h3>
  • For a brief period of time, this medicine is used to relieve sporadic constipation.
  • It is an osmotic laxative, which means that it works by drawing water into the intestines, which aids in causing bowel movement.
<h3>What dosage of milk of magnesia is recommended for constipation?</h3>
  • Take Milk of Magnesia once day, preferably before bed, in divided doses, or as prescribed by a physician.
  • suggested dosage: 30 mL to 60 mL for adults and kids 12 years of age and older. 15 mL to 30 mL for children aged 6 to 11 years.

learn more about milk of magnesia here

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the question you are looking for is

People often take milk of magnesia to reduce the discomfort associated with acid stomach or heartburn. The recommended dose is 1 teaspoon, which contains 4.00x 10^{2} mg of Mg(OH)_2. What volume of an HCl solution with a pH of 1.3 can be neutralized by one dose of milk of magnesia? If the stomach contains 2.00x10^{2}mL of pH 1.3 solution, is all the acid neutralized? If not, what fraction is neutralized?

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A sample contains 1.29×1022 atoms of Cs. Calculate the amount of Cs.
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Use <em>Avogadro’s number</em> to convert atoms of Cs to moles of Cs.

Moles of Cs = 1.29×10²² atoms Cs × (1 mol Cs /6.022 × 10²³ atoms Cs) = 0.0214 mol Cs

4 0
3 years ago
What is the balanced molecular equation for the reaction between nitric acid and calcium hydroxide?
hodyreva [135]
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5 0
3 years ago
How many moles of H2O are in 64.0 g of H2O
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Answer:

Explanation:

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Number of moles of C₂H₂ = molar mass of C₂H₂  

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the number of H₂O moles formed = a number of C₂H₂  moles reacted.

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8 0
2 years ago
The nickel(II) ion is commonly dissolved in solution using nickel(II) nitrate hexahydrate, Ni(NO3)2.6H2O. The nickel(II) ion pre
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at pH = 10 
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Ksp = S [10⁻⁴ + 2S]²
Ksp is very small so the molar solubility of OH⁻ will be very small
so (10⁻⁴ + 2S) is about 10⁻⁴
so Ksp = S x 10⁻⁸
S = \frac{6 x 10^{-16} }{10^{-8} } = 6 x 10⁻⁸ M
8 0
3 years ago
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