The ionization energy of chlorine is lower than the ionization energy for

Calculate the concentration of all ions present in each of the following solutions of strong electrolytes.

MAVERICK [17]

Answer:

a. Ca2+ 1M ; NO3- 2M

b. Na+ 4M ; SO4-2 2M

c. NH4+ , Cl- 0,186M

d. K+ 0,056M ; PO4-3 0,0188 M

Explanation:

Here are the ionization equations

Ca(NO3)2 ----> Ca2+ + 2NO3-

Na2SO4 ------> 2Na+ + SO4-2

NH4Cl ------> NH4+ + Cl-

K3PO4 -----> 3K+ + PO4-3

Concentrations must be in Molarity (moles/L)

Ca(NO3)2 0,1 mole in 100mL

100mL = 0,1 L

Molarity Ca(NO3)2 1M (0,1 /0,1)

Ca(NO3)2 ----> Ca2+ + 2NO3-

1 M 1M 2M

Na2SO4 2,5 moles in 1,25L

Molarity Na2SO4 2,5 moles /1,25L = 2M

Na2SO4 ------> 2Na+ + SO4-2

2M 4M 2M

5.00 g of NH4Cl in 500mL

We have to resort to the molar mass

Let's make the rule of three

500mL ______ 5g

1000mL _____ (1000mL . 5g) / 500mL = 10 g

(These are the grams in 1L, so with the molar mass, we get the moles)

Mass / Molar mass = moles --> 10g / 53,5 g/m = 0.186 moles

NH4Cl ------> NH4+ + Cl-

0,186 M 0,186M + 0,186M

1.00 g K3PO4 in 250.0 mL

(The same as before)

250 mL ________1 g

1000 mL _______ (1000 mL . 1 g) /250mL = 4 g

These are the grams in 1L, so with the molar mass, we get the moles

Mass / Molar mass = moles --> 4g /212,26 g/m = 0,0188 moles

K3PO4 -----> 3K+ + PO4-3

0,0188 M 0,056M + 0,0188 M

7 0

3 years ago

When a polar molecule causes a charge redistribution in a nonpolar molecule, what are the molecules of the mixture most likely e

White raven [17]

Answer is: dipole-induced dipole interactions.

Intermolecular forces are the forces between molecules or particles.

There are several types of intermolecular forces: hydrogen bonding, ion-induced dipole forces, ion-dipole forces and van der Waals forces.

A dipole-induced dipole interaction is a weak attraction that results when a polar molecule induces a dipole in a nonpolar molecule by disturbing the arrangement of electrons in the nonpolar species.

4 0

3 years ago

Read 2 more answers

Complete end balance the reaction :copper plus hydrobromic acid

Reika [66]

Answer:

The correct answer is - 2Cu + 4HBr → 2H[CuBr2] + H2

Explanation:

Copper (Cu) and hydrobromic acid (HBr), which is a dissolved form of hydrogen bromide in the water, react and produce hydrogen dibromidocuprate (I) and hydrogen molecules.

The complete and balanced equation is -

2Cu + 4HBr → 2H[CuBr2] + H2

This reaction takes place in the medium of ester. Copper is in the suspension form in this reaction.

Thus, the correct answer is - 2Cu + 4HBr → 2H[CuBr2] + H2

5 0

3 years ago

Given 6.0 mol of N2 are mixed with 12.0 mol of H2. Equation: N2 + 3H2--> 2NH3

andrey2020 [161]

1) Excess reagent

1 mol N2 / 3 mol H2

6.0 mol N2 *3 mol H2 / 1 mol N2 = 18 mol H2

18mol H2 > 12 mol H2 => H2 is limiting (you need 18 mol H2 to use all the 6 mol N2), then N2 is in excees.

12.0 mol H2 * 1mol N2/ 3 mol H2 = 4 mol N2 is the quantity that will react, then the excess is 6 mol N2 - 4 mol N2 = 2 mol N2

2) NH3 produced

12 mol H2 * [2 mol NH3 / 3 mol H2] = 8 mol NH3

Aslso, 4 mol N2 *[2molNH3 / 1 molN2] = 8 mol NH3, the same result.

3) Yield

80% * 8 mol NH3 = 6.4 mol NH3

5 0

3 years ago

What is the difference between qualitative data and quantitative data?

astraxan [27]

Quantitative data can be counted, measured, and expressed using numbers. Qualitative data is descriptive and conceptual.

7 0

3 years ago