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WARRIOR [948]
3 years ago
7

Which description refers to fog?

Chemistry
1 answer:
Aneli [31]3 years ago
4 0

Answer:

The correct option is;

Is found near bodies of water

Explanation:

Fog forms as an aerosol which is visible to the eye that normally consists of tiny condensed water vapor droplets or crystals of ice that is formed when air that is warm comes in contact with cool air close to the Earth's surface. Fog can be taken as a stratus like cloud that lies close to the Earth's surface and it normally forms due to the presence of water bodies that are nearby, the topography of the area or the conditions of the wind.

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Silver nitrate reacts with aluminum chloride to form the insoluble compound, silver chloride. The reaction proceeds according to
viva [34]

The theoretical yield of silver chloride, AgCl is 5.2109 g

The balanced equation for the reaction is given below:

<h3>3AgNO₃(aq) + AICI₃(aq) —> Al(NO₃)₃ (aq) + 3AgCl (s) </h3>

Next, we shall determine the mass of aluminum chloride, AICI₃ that reacted and the mass of silver chloride, AgCl produced from the balanced equation. This is illustrated below:

Molar mass of AICI₃ = 133.34 g/mol

Mass of AICI₃ from the balanced equation = 1 × 133.34 = 133.34 g

Molar mass of AgCl = 143.32 g/mol

Mass of AgCl from the balanced equation = 3 × 143.32 = <em>429.96 g</em>

<h3>SUMMARY</h3>

From the balanced equation above,

133.34 g of AICI₃ reacted to produce 429.96 g of AgCl.

Finally, we shall determine the theoretical yield of AgCl by the reaction of 1.616 g of AICI₃ as follow:

From the balanced equation above,

133.34 g of AICI₃ reacted to produce 429.96 g of AgCl.

Therefore,

1.616 g of AICI₃ will react to produce = \frac{1.616 * 429.96}{133.34} = 5.2109 g of AgCl.

Thus, the theoretical yield of silver chloride, AgCl is 5.2109 g

Learn more: brainly.com/question/24653699

3 0
3 years ago
Copper can have improved wear resistance if alloyed with ceramic alumina, Al2O3. If a copper alloy has 7.7 wt % Al2O3, what is i
vitfil [10]

The composition in mol% of the elements are :

  • 4.91%  of Al₂O₃ in alloy  
  • 95.08% of Cu in alloy

<u>Given data : </u>

Weight percentage of copper alloy = 7.7 wt %

Assume weight of alloy = 100 grams

<h3>Applying the weight percentage </h3>

mass of Al₂O₃ in alloy = 7.7 gm

Mass of Cu in alloy = 100 - 7.7 = 92.3 gm

<u />

<u>First step : calculate the mole of elements</u>

i) moles of Al₂O₃ in alloy

 = mass of Al₂O₃  in alloy /  Atomic mass of Al₂O₃

 = 7.7 gm  / 102 gm/mol

 = 0.075 mol

ii) moles of Cu in alloy

 = mass of Cu in alloy / Atomic mass of Cu

 = 92.3 gm / 63.5 gm/mol

 = 1.45 mol

Therefore the total number of moles in the alloy = 0.075 + 1.45 = 1.525

<u>Next step : Determine the mole </u><u>percentages </u>

i) Mole percentage of Al₂O₃ in alloy  

= ( 0.075 ) / 1.525  * 100

= 4.91%

ii) Mole percentage of Cu in alloy

= ( 1.45 ) / 1.525 * 100

= 95.08%

<u />

Hence we can conclude that The composition in mol% of the elements are : 4.91%  of Al₂O₃ in alloy and  95.08% of Cu in alloy.

Learn more about alloys : brainly.com/question/716507

4 0
2 years ago
When a bond is created how many valence electrons are needed to fill an octet?
love history [14]
To fill an octet you need 8 electrons..
6 0
3 years ago
guys please help me i've been struggling with this question all school day (what reaction is ___ Mg + ____ H₂SO₄ --&gt; ____ H₂
love history [14]

Answer:

Single replacement reaction

Explanation:

It's already balanced so it would just be Mg + H2SO4 --> H2 + MgSO4

The formula for a single replacement reaction is

A + BC --> B + AC

A=Mg

B=H2

C=SO4

5 0
3 years ago
Use complete sentences to explain how you determined the mass of oxygen in the compound produced in the virtual lab, and how the
lubasha [3.4K]
You can determine its weight by simply weighing it. Then, you use the mass to divide to the empirical molar mass. This is done by getting the molar ratio of the individual elements within that compound. Use the least amount of moles of the elements and divide it with the rest. Then, you'd get the empirical formula.
5 0
3 years ago
Read 2 more answers
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