Answer:
The correct answer is 1.778 milligrams per liter.
Explanation:
Based on the given information, the concentration of chlorine gas given is 27 pounds or 27*453.59 = 12327.93 grams.
The quantity of water given is 750000 gallons or 750000 * 3.754 = 2815500 L
The concentration of chlorine used up by the microorganism is 2.6 mg/L or 0.0026 gm/L.
Thus, for 2815500 L of water, the amount of chlorine used is,
= 2815500 * 0.0026
= 7320.3 grams
The left quantity of chlorine is 12327.93 - 7320.3 = 5007.63 grams
The concentration of residual chlorine is,
= 5007.63 g/2815500 = 0.00177859 or 1.778 mg/L.
The answer is hydrolysis. Glycogen is a polymer of glucose linked together by α(1→4) glycosidic bonds and α(1→<span>6)-linked branches. During hydrolysis, a water molecule is consumed for every bond that is hydrolyzed. Attached diagram is a clear description of this process. In biology, the degradation of glycogen to glucose is referred to as glycogenolysis. </span>
Hey there!
For this we can use the combined gas law:
We are only working with pressure and temperature so we can remove volume.
P₁ = 2 atm
T₁ = 27 C
P₂ = 2.2 atm
Plug these values in:
Solve for T₂.
Convert this to kelvin and get 302.85 K, which is closest to B. 330 K.
Hope this helps!
Answer:
Mg S2 O3
Explanation:
.691 g of Mg is .284 mole
1.84 g of S is .5739 mole
1.365 g of O is .8531 mole you can see the ratio is ~ 1 :2 :3
Mg S2 O3
Answer:
The answer is:
B
Explanation:
The compound in Option B is Methane.
Methane is known to be a compound which has two elements, carbon and hydrogen. It has a central atom which is surrounded by four hydrogen atoms. It's chemical formula is CH4.
Methane's outer atoms are dipoles and are in the same direction. This makes the overall molecule non-polar. The compound itself has non-polar bonds and it is non-polar itself.
