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lina2011 [118]
3 years ago
5

Which types of particles are charged and located within the nucleus of an atom?

Chemistry
2 answers:
exis [7]3 years ago
6 0

Answer : The correct option is, protons

Explanation :

As we know that an atom is the smallest unit of a matter that consist of three subatomic particles which are electrons, protons and neutrons.

The protons and the neutrons are located inside the nucleus or center of the nucleus where the mass of the an atom is concentrated and the electrons are located around the nucleus.

The protons are positively charged, the electrons are negatively charged and the neutrons are neutral that means it has no charge.

Hence, the particle protons are positively charged and located within the nucleus of an atom.

Readme [11.4K]3 years ago
3 0

Answer:

Protons, electron, and neutrons

Explanation:

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Empirical formulas can be determined from the percent composition of a compound. In order to determine its molecular formula, it is necessary to know the molar mass of the compound. Chemists use an instrument called a mass spectrometer to determine the molar mass of compounds.

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Consider the reaction below in a closed flask. At 200 o C, the equilibrium constant (Kp) is 2.40 × 103 . 2 NO (g)  N2 (g) + O2
olga55 [171]

Explanation:

Since, the given reaction is as follows.

       2NO(g) \rightleftharpoons N_{2}(g) + O_{2}(g)

Initial:    36.1 atm                 0          0

Change:    2x                      x           x

Equilibrium: (36.1 - 2x)       x            x

Now, expression for K_{p} of this reaction is as follows.

            K_{p} = \frac{[N_{2}][O_{2}]}{[NO]^{2}}

As the initial pressure of NO is 36.1 atm. Hence, partial pressure of O_{2} at equilibrium will be calculated as follows.

              K_{p} = \frac{[N_{2}][O_{2}]}{[NO]^{2}}

        2.40 \times 10^{3} = \frac{x \times x}{(36.1 - 2x)^{2}}

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Thus, we can conclude that partial pressure of O_{2} at equilibrium is 18.1 atm.

5 0
3 years ago
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Percent of water in Na2CO3 • 10H2O
Troyanec [42]
Hey there! 

In order to solve for the percentage of water in the compound, you will first need to find its total molar mass. You can do this by adding up the molar masses of each individual element in the compound. Then, you will divide the mass that you find of the water molecules by the total mass to get the percentage. 

→ Na₂CO₃ ×<span> 10 H</span>₂<span>O

</span>→ Na₂ = 22.9898 × 2 = 45.9796
→ C = 12.0107
→ O₃ = 15.999 × 3 = 47.997
→ 10 H₂O = 18.015 × 10 = 180.15

Now, just add all of those numbers up for the total molar mass. 

→ 45.9796 + 12.0107 + 47.997 + 180.15 = <span>286.1373
</span>
The last step is to divide the molar mass of the 10 water molecules by the total mass. 

→ 180.15 ÷ 286.1373 = <span>0.62959 </span>≈ 0.63

Your answer will be about 63%. 

Hope this helped you out! :-)
5 0
3 years ago
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