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Tpy6a [65]
1 year ago
14

Identify the triangle, ABC, which has a 52∘ angle and a 83∘ angle.

Mathematics
2 answers:
Murrr4er [49]1 year ago
8 0

Answer:

Acute by edehhw h egdue bw jehrhr

goldenfox [79]1 year ago
4 0
It’s acute cuz it’s less then 90 degrees each angle
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the difference between 2 whole numbers is 66. the ratio of the 2 numbers is 2:5, what are the 2 numbers​
shtirl [24]

Answer:

44 and 110

Step-by-step explanation:

The ratio of the 2 numbers = 2 : 5 = 2x : 5x ( x is a multiplier ) , thus

difference = 5x - 2x = 3x , then

3x = 66 ( divide both sides by 3 )

x = 22

Thus

2x = 2 × 22 = 44

5x = 5 × 22 = 110

The 2 numbers are 44 and 110

8 0
3 years ago
I beeps help please
Sergeeva-Olga [200]
Answer is in the file
7 0
2 years ago
A washer and a dryer cost $911 combined. The washer costs $39 less than the dryer. What is the cost of the dryer?
Gemiola [76]
$475 is the dryer, and the washer is $436
3 0
2 years ago
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Little Snail is going to visit his friend over at the next pond, 3 miles away. He can crawl ( 1/2. 1/3, 1/4, 3/4, 2/3 ) of a mil
KIM [24]

Solution :

It is given that Little Snail is going to visit one of his friend at the pond which is 3 miles away.

When the snail crawls 1/2 of a mile per day, it will take him, $1 \times \frac{2}{1} \times 3$

   =  6 days to get to the next pond.

When the snail crawls 1/3 of a mile per day, it will take him, $1 \times \frac{3}{1} \times 3$

   =  9 days to get to the next pond.

When the snail crawls 1/4 of a mile per day, it will take him, $1 \times \frac{4}{1} \times 3$

   = 12 days to get to the next pond.

When the snail crawls 3/4 of a mile per day, it will take him, $1 \times \frac{4}{3} \times 3$

   =  4 days to get to the next pond.

When the snail crawls 2/3 of a mile per day, it will take him, $1 \times \frac{3}{2} \times 3$

   =  4.5 days to get to the next pond.

3 0
3 years ago
What is the speed (approximately) of a 2.5-kilogram mass after it has fallen freely from rest through a distance of 12 meters?
Norma-Jean [14]

Answer:

15.3 m/s

Step-by-step explanation:1) Find the gravitational potential energy using the equation :

     PE_g=mgh

    PE_g=2.5(12)(9.8)\\PE_g=294

2) Then use the equation for kinetic energy to solve for the velocity:

     KE=\frac{1}{2} mv^{2}

     294=\frac{1}{2}(2.5)(v^2)\\235.2=v^2\\\sqrt{235.2} =v\\15.3 m/s=v

6 0
2 years ago
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