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Karo-lina-s [1.5K]
2 years ago
10

Refer to the number line. Find the coordinate of point D that is 7/16 M to J. of the distance from M to J.​

Mathematics
1 answer:
Usimov [2.4K]2 years ago
4 0

The coordinate of point D that divides segment MJ in the ratio 7/16 is (13, 8)

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

An independent variable is a variable that does not depends on other variable while a dependent variable is a variable that depends on other variable.

Let us assume that point M is at (20, 1) and point J is at (4, 17), hence:

If point D(x, y) is 7/16 M to J, then:

x = (7/16)(4 - 20) + 20 = 13

y = (7/16)(17 - 1) + 1 = 8

The coordinate of point D that divides segment MJ in the ratio 7/16 is (13, 8)

Find out more on equation at: brainly.com/question/2972832

#SPJ1

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Answer:

4/15

Step-by-step explanation:

4/10*6/9

2/5*2/3

4/15

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3 years ago
50= p• 0.05•2<br> Solve
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Answer:

P=500

Step-by-step explanation:

My reasoning is multiply 0.05 and 2 and you get 0.1. Then you divide 0.1 out of 50 and get 500. Too check the answer you take 500 and multiply it by 0.05 and then  multiply it by 2 and you should get an answer of 50 like it says in the equation.

3 0
3 years ago
Read 2 more answers
A medical researcher wondered if there is a significant difference between the mean birth weight of boy and girl babies. Random
Yuliya22 [10]

Answer:

b) independent samples t-test

t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154  

p_v =2*P(t_{8}>0.154) =0.881  

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).  

Step-by-step explanation:

The system of hypothesis on this case are:  

Null hypothesis: \mu_1 = \mu_2  

Alternative hypothesis: \mu_1 \neq \mu_2  

Or equivalently:  

Null hypothesis: \mu_1 - \mu_2 = 0  

Alternative hypothesis: \mu_1 -\mu_2\neq 0  

Our notation on this case :  

n_1 =5 represent the sample size for group 1  

n_2 =5 represent the sample size for group 2  

We can calculate the mean and deviation for eaach group with the following formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

\bar X_1 =5.92 represent the sample mean for the group 1  

\bar X_2 =5.74 represent the sample mean for the group 2  

s_1=1.88 represent the sample standard deviation for group 1  

s_2=1.81 represent the sample standard deviation for group 2  

If we see the alternative hypothesis we see that we are conducting a bilateral test and with independnet samples t test.

b) independent samples t-test

The statistic is given by this formula:  

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}}+\frac{S^2_2}{n_2}}  

And now we can calculate the statistic:  

t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154  

The degrees of freedom are given by:  

df=5+5-2=8

And now we can calculate the p value using the altenative hypothesis:  

p_v =2*P(t_{8}>0.154) =0.881  

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).  

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Answer:

76 mL

Step-by-step explanation:

40*19/10

40*19= 760 / 10 = 76mL

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