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Andre45 [30]
3 years ago
12

Three relationships are described below: I. The amount of fuel used on a trip increases as the size of the car increases and as

the distance traveled increases. II. As the number of people helping mow a lawn increases, the time it takes to mow the lawn decreases. III. The cost of having a house painted increases as the size of the house increases. What type of variation describes each relationship?
Mathematics
1 answer:
jekas [21]3 years ago
5 0

Variation are of 2 types: Direct variation that states 'if x increases, y increases'. And inverse variation which states ' if x increases, y decreases and y increases x increases'.

1. The amount of fuel used on a trip increases as the size of the car increases and as the distance traveled increases. = Direct variation

2. As the number of people helping mow a lawn increases, the time it takes to mow the lawn decreases = Inverse variation

3. The cost of having a house painted increases as the size of the house increases. = Direct variation

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goldfiish [28.3K]

Answer:

No mistake

Step-by-step explanation:

2x + y = 5

x - 2y = 10

y = 5 - 2x

x - 2(5 - 2x) = 10

x - 10 + 4x = 10

5x - 10 = 10

5x = 20

x = 4

2(4) + y = 5

y =  -3

She made no mistake

You can check by plugging in x = 4 and y = -3 into the original equations . They fit exactly.


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Step-by-step explanation:

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if you practice a musical instrument each day for 2/3 of an hour how many hours of practice would you get in each week?
RideAnS [48]
In order to find the answer of the given problem above, we need to make the solution below:
Given: 2/3 of an hour = practice each day
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Question 8 of 10
Andreyy89

Median and IQR are the most appropriate measures of center and spread for this data set.

<h3>Why are Median and IQR the most appropriate?</h3>

Among the 3 central tendencies that includes the mean, median and mode; the median is the better measure because of the followings:

  • Mean is affected by extreme values
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  • Mean may not represent the nature of the data whether skewed right or left.

Also, the median as the middle entry is not affected by extreme items or outliers, so the median is better than mean,

Furthermore, for the measure of spread, the IQR is better since extreme items will show higher std deviation and also some outliers mislead.

Therefore, Option B is correct.

Read more about measures of center

brainly.com/question/10610456

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Answer:

see explanation for number line\ $29$

Step-by-step explanation:

this is the answer guys.

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