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siniylev [52]
3 years ago
14

A distribution is negatively skewed if which of these statements is true about the density curve that represents it?

Mathematics
1 answer:
natima [27]3 years ago
8 0
The left tail is longer than the right.
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Please Help me
inessss [21]
The answer is 27 because the are nine options which can be recombined in 3 independent ways. Therefore, 9*3=27
7 0
3 years ago
Read 2 more answers
6x+3&lt;7-2x<br> I’m not sure if I’m doing it right so an explanation would be nice
enot [183]

Answer:

x<0.5

Step-by-step explanation:

this is just like simplifiying equations if you've done that before

first you want to isolate the variable, so you want to combine the values of x (in this case it's 6x and the -2x)

so you can either add 2x to both sides or you can subtract 6x on both sides, in this case ill just add 2x to both sides.

Then you subtract 3 from both sides to get 8x<4

after you get that, you want to divide both sides by 8, and you generally want to do that step last, it makes it easier, and you get x<1/2 or 0.5

just a reminder that with working with inequalities, you want to remember to flip the direction the inequality is whenever you divide by a negative number

7 0
3 years ago
If 30.0 moles of oxygen are used, how many grams of water will form?
liberstina [14]

Answer:

3

Step-by-step explanation:

8 0
3 years ago
Given f(x), match each expression to its correct value
Murljashka [212]

Answer:

-11, f(-5)    1

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Let U1, ..., Un be i.i.d. Unif(0, 1), and X = max(U1, ..., Un). What is the PDF of X? What is EX? Hint: Find the CDF of X first,
Kryger [21]

Answer:

E(X)= n \int_{0}^1 x^n dx = n [\frac{1}{n+1}- \frac{0}{n+1}]=\frac{n}{n+1}

Step-by-step explanation:

A uniform distribution, "sometimes also known as a rectangular distribution, is a distribution that has constant probability".

We need to take in count that our random variable just take values between 0 and 1 since is uniform distribution (0,1). The maximum of the finite set of elements in (0,1) needs to be present in (0,1).

If we select a value x \in (0,1) we want this:

max(U_1, ....,U_n) \leq x

And we can express this like that:

u_i \leq x for each possible i

We assume that the random variable u_i are independent and P)U_i \leq x) =x from the definition of an uniform random variable between 0 and 1. So we can find the cumulative distribution like this:

P(X \leq x) = P(U_1 \leq 1, ...., U_n \leq x) \prod P(U_i \leq x) =\prod x = x^n

And then cumulative distribution would be expressed like this:

0, x \leq 0

x^n, x \in (0,1)

1, x \geq 1

For each value x\in (0,1) we can find the dendity function like this:

f_X (x) = \frac{d}{dx} F_X (x) = nx^{n-1}

So then we have the pdf defined, and given by:

f_X (x) = n x^{n-1} , x \in (0,1)  and 0 for other case

And now we can find the expected value for the random variable X like this:

E(X) =\int_{0}^1 s f_X (x) dx = \int_{0}^1 x n x^{n-1}

E(X)= n \int_{0}^1 x^n dx = n [\frac{1}{n+1}- \frac{0}{n+1}]=\frac{n}{n+1}

6 0
3 years ago
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