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Rudiy27
3 years ago
11

How i can answer this question

Mathematics
2 answers:
timurjin [86]3 years ago
8 0

Answer:

B,C and D

Step-by-step explanation:

They all expand back to 16x + 20.

sweet-ann [11.9K]3 years ago
7 0

Answer:

B

D

C

Glad I coild help you out.

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What do i type? please help me.
sergij07 [2.7K]

Answer:

x = 10; x = 0

Step-by-step explanation:

x < 29 means x is less than 29. Any number less then 29 is a solution.

For example, pick x = 10. Since 10 < 29, x = 10 is a solution. How do we know x = 10 is a solution?

We start with x < 29.

Now replace x with 10.

10 < 29

Since 10 < 29 is a true statement, then x = 10 is a solution.

Now pick another number less than 29. For example, oick 0.

x = 0 is a solution.

Proof:

x < 29

Replace x with 0:

0 < 29

Since 0 < 29 is a true statement, then x = 0 is a solution.

You can give more solutions just by picking any numbers that are less than 29, such as 1, 2, 3, 15, 28, 23, -5, -18, etc.

Answer: x = 10; x = 0

4 0
3 years ago
Read 2 more answers
Solve the equation for b.
Mkey [24]

Answer:

Move all terms to the left side and set equal to zero. Then set each factor equal to zero.

b =  M /4  +  9 x

7 0
3 years ago
Read 2 more answers
Find the slope of the line on the graph.
vovikov84 [41]

Answer:

1/2

Step-by-step explanation:

Find two points on the line

(2,0) and (4,1)

The slope is given by

m= (y2-y1)/(x2-x1)

   =(1-0)/(4-2)

   = 1/2

8 0
3 years ago
Algebraic expression<br> The number of jelly beans divided into 9 piles
Mila [183]
The expression would be j / 9. J is a variable.
6 0
4 years ago
Given points A (1, 2/3), B (x, -4/5), and C (-1/2, 4) determine the value of x such that all three points are collinear
AlladinOne [14]

Answer:

x=\frac{83}{50}

Step-by-step explanation:

we know that

If the three points are collinear

then

m_A_B=m_A_C

we have

A (1, 2/3), B (x, -4/5), and C (-1/2, 4)

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

step 1

Find the slope AB

we have

A(1,\frac{2}{3}),B(x,-\frac{4}{5})

substitute in the formula

m_A_B=\frac{-\frac{4}{5}-\frac{2}{3}}{x-1}

m_A_B=\frac{\frac{-12-10}{15}}{x-1}

m_A_B=-\frac{22}{15(x-1)}

step 2

Find the slope AC

we have

A(1,\frac{2}{3}),C(-\frac{1}{2},4)

substitute in the formula

m_A_C=\frac{4-\frac{2}{3}}{-\frac{1}{2}-1}

m_A_C=\frac{\frac{10}{3}}{-\frac{3}{2}}

m_A_C=-\frac{20}{9}

step 3

Equate the slopes

m_A_B=m_A_C

-\frac{22}{15(x-1)}=-\frac{20}{9}

solve for x

15(x-1)20=22(9)

300x-300=198

300x=198+300

300x=498

x=\frac{498}{300}

simplify

x=\frac{83}{50}

8 0
4 years ago
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