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2 years ago

The product of 2r- t and 5m + 3=

Mathematics

1 answer:

DaniilM [7]2 years ago

7 0

Answer: $10rm+6r-5tm-3t$

Step-by-step explanation:

$(2r-t)(5m+3)\\\\=10rm+6r-5tm-3t$

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You deposit $1,000 in the bank and leave it for five years at 3 percent annual interest, making no additional transactions on th

svetlana [45]

Answer: you would withdraw $1150

Step-by-step explanation:

We would apply the formula for determining simple interest which is expressed as

I = PRT/100

Where

I represents interest paid on the amount deposited.

P represents the principal or amount deposited.

R represents interest rate

T represents the duration in years.

From the information given,

P = 1000

R = 3%

T = 5 years

I = (1000 × 3 × 5)/100 = $150

The amount that you would withdraw including principal and interest would be

1000 + 150 = $1150

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4 years ago

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If x represents the amount Rita earns each week, which expression represents the amount she earns in a year?

Sphinxa [80]

There are 52 weeks in a year, so 52x represents how much she earns in a year.

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3 years ago

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Enter the number that is 10 more than 642

Soloha48 [4]

642+10= 652//////////////

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3 years ago

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What is the value of X?

Marizza181 [45]

Answer:

Step-by-step explanation:

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3 years ago

Joy recorded the distances she walked each day for five days. How far did she walk in 5 days? Line plot: 3 xs on 1/3 1 x on 1/2

kotykmax [81]

Answer:

$2\frac{1}{6}\approx 2.167$ units.

Step-by-step explanation:

We have been given that Joy recorded the distances she walked each day for five days.

To find the distance traveled be Joy in 5 days we will add the distances covered by Joy each day.

As there are 3 dots on 1/3, this means that Joy traveled 1/3 units on 3 days.

Since there is 1 dot on 1/2 and on dot on 2/3, so this means that Joy walked 1/2 units one day and 2/3 units another day.

Let us add all these distances.

$\text{Total distance walked by Joy in 3 days}=3\times\frac{1}{3}+\frac{1}{2}+\frac{2}{3}$

$\text{Total distance walked by Joy in 3 days}=\frac{1*3}{3}+\frac{1}{2}+\frac{2}{3}$

Let us have a common denominator.

$\text{Total distance walked by Joy in 3 days}=\frac{3*2}{3*2}+\frac{1*3}{2*3}+\frac{2*2}{3*2}$

$\text{Total distance walked by Joy in 3 days}=\frac{6}{6}+\frac{3}{6}+\frac{4}{6}$

$\text{Total distance walked by Joy in 3 days}=\frac{6+3+4}{6}$

$\text{Total distance walked by Joy in 3 days}=\frac{13}{6}$

$\text{Total distance walked by Joy in 3 days}=2\frac{1}{6}$

Therefore, Joy traveled $2\frac{1}{6}\approx 2.167$ units in 5 days.

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4 years ago