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Vera_Pavlovna [14]
4 years ago
11

You deposit $1,000 in the bank and leave it for five years at 3 percent annual interest, making no additional transactions on th

is account. At the end of the five years, you withdraw the principal and any accumulated interest; the amount you would withdraw would be ________.
Mathematics
2 answers:
Lena [83]4 years ago
8 0

Answer:

$1,159.27

Step-by-step explanation:

$1000 * 3%= 30     $1,030

$1,030 * 3%=30.9      $1,060.9

$1,060.9 * 3%=31.83   $1,092.73

$1,092.73 * 3%=32.78    $1,125.51

$1,125.51 * 3%=33.76        $1,159.27

svetlana [45]4 years ago
4 0

Answer: you would withdraw $1150

Step-by-step explanation:

We would apply the formula for determining simple interest which is expressed as

I = PRT/100

Where

I represents interest paid on the amount deposited.

P represents the principal or amount deposited.

R represents interest rate

T represents the duration in years.

From the information given,

P = 1000

R = 3%

T = 5 years

I = (1000 × 3 × 5)/100 = $150

The amount that you would withdraw including principal and interest would be

1000 + 150 = $1150

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3 years ago
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the points (3, 9) and (-3, -9) ate plotted on the coordinate plane using the equation y=a . x ... - did
slava [35]

See the explanation

<h2>Explanation:</h2><h2></h2>

Here we have the following points:

(3,9) \ and \ (-3,-9)

The point-slope form of the equation of a line is:

y=ax+b \\ \\ \\ a:Slope \\ \\ b:y-intercept

So the slope can be found as:

a=\frac{-9-9}{-3-3} \\ \\ a=\frac{-18}{-6} \\ \\ a=3

So:

y=3x+b \\ \\ \\ Finding \ b: \\ \\ For \ x=3, \ y=9: \\ \\ \\ So: \\ \\ 9=3(3)+b \\ \\ b=9-9 \\ \\ b=0

So the equation is finally:

y=3x

This line passes through and is shown below.

<h2>Learn more:</h2>

About lines: brainly.com/question/14427236#

#LearnWithBrainly

8 0
4 years ago
The cylinder below has r = 10 inches and a volume of 6283 cubic inches to
Reil [10]
V= piR^2(h)
6283=pi(10^2)(h)
6283=pi(100)h
height = 6283/(pi(100))
then round to the nearest inch
4 0
3 years ago
The length and width of a rectangle are measured as 30cm and 24cm, respectively, with an error in measured of
larisa [96]

Answer:

The maximum error in the calculated area of rectangle is 5.4 cm².

Step-by-step explanation:

Given : The length and width of a rectangle are measured as 30 cm and 24 cm, respectively, with an error in measured of  at most 0.1 cm in each.

To find : Use differentials to estimate the maximum error in the calculated area of rectangle ?

Solution :

The area of the rectangle is A=l\times w

The derivative of the area is equal to the partial derivative of area w.r.t. length times the change in length plus the partial derivative of area w.r.t. width times the change in width.

i.e. dA=\frac{\partial A}{\partial L}\Delta L+\frac{\partial A}{\partial W}\Delta W

Here, \frac{\partial A}{\partial L}=30,\ \frac{\partial A}{\partial W}=24 ,\ \Delta L=0.1,\ \Delta W=0.1

Substitute the values,

dA=(30)(0.1)+(24)(0.1)

dA=3+2.4

dA=5.4

Therefore, the maximum error in the calculated area of rectangle is 5.4 cm².

7 0
3 years ago
Pls help pls ill give u a braniest if you help me
alexandr1967 [171]

Answer:

B

Step-by-step explanation:

y = (x + 1)/x

xy = x + 1

xy - x = 1

x(y - 1) = 1

x = 1/(y - 1)

Interswitch variables

f^-1(x) = 1/(x - 1)

4 0
4 years ago
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