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2 years ago

Please help me. It’s due asap!

Mathematics

1 answer:

Montano1993 [528]2 years ago

7 0

Answer A

Step-by-step explanation:

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Find the value of x and y for the equation x+y5 7x+9y=6

Nastasia [14]

Answer:

$x = \frac{39}{2}$

$y = -\frac{29}{2}$

Step-by-step explanation:

Given

$x + y= 5$ --- (1)

$7x + 9y = 6$ ---- (2)

Required

Find x and y

Make x the subject in (1)

$x + y= 5$

$x = 5 - y$

Substitute 5- y for x in (2)

$7x + 9y = 6$

$7(5 - y) + 9y = 6$

Open bracket

$35 -7 y + 9y = 6$

Collect like terms

$-7y + 9y = 6 - 35$

$2y = -29$

Divide both sides by 2

$y = -\frac{29}{2}$

Substitute this for y in $x = 5 - y$

$x = 5 - (-\frac{29}{2})$

$x = 5 +\frac{29}{2}$

L.C.M

$x =\frac{10+29}{2}$

$x = \frac{39}{2}$

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3 years ago

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Step-by-step explanation:

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Solve for x 2/x+2 + 1/5 = 6/x+5 x = 0 x = –13 x = 13 x = 0 and x = 13

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$\dfrac{2}{x+2}+\dfrac{1}{5}=\dfrac{6}{x+5}\qquad\text{multiply both sides by 5}\\\\\dfrac{10}{x+2}+1=\dfrac{30}{x+5}\\\\\dfrac{10}{x+2}+\dfrac{x+2}{x+2}=\dfrac{30}{x+5}\\\\\dfrac{10+x+2}{x+2}=\dfrac{30}{x+5}\\\\\dfrac{x+12}{x+2}=\dfrac{30}{x+5}\qquad\text{cross multiply}\\\\(x+12)(x+5)=30(x+2)\qquad\text{use distributive property}\\\\(x)(x)+(x)(5)+(12)(x)+(12)(5)=(30)(x)+(30)(2)\\\\x^2+5x+12x+60=30x+60\qquad\text{subtract 60 from both sides}\\\\x^2+17x=30x\qquad\text{subtract 30x from both sides}$

$x^2-13x=0\\\\x(x-13)=0\iff x=0\ \vee\ x-13=0\qquad\text{add 13 to both sides}\\\\\boxed{x=0\ \vee\ x=13}$

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3 years ago