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Leya [2.2K]
3 years ago
12

Consider the equation y = (x + 2)^2 – 3. What is the length of the focal width of the parabola?

Mathematics
2 answers:
coldgirl [10]3 years ago
7 0

Answer:

1

Step-by-step explanation:

i just took the quiz

likoan [24]3 years ago
6 0

Answer:

The length of the focal width of the parabola is 1.

Step-by-step explanation:

Suppose we have a parabola with the following equation:

(x - h)^2 = 4p(y - k)

The centre is at point (h,k).

The length of the focal width is of |4p|.

In this question:

We want to place in the general format. So

y = (x+2)^2 - 3

(x+2)^2 = 1(y + 3)

Comparing, we have that 4p = 1. So the length of the focal width of the parabola is 1.

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7 0
4 years ago
If you can tell me what the missing number is.
Orlov [11]

Answer:

6

Step-by-step explanation:

So, to start answering this, lets recall the formula for a rectangles volume:

This formula is :

V=h*w*l

Lets plug in what we know, and solve for the missing variable.

We know that height(h) is 7.

We know that width(w) is 9.

We know that volume(V) is 378.

We are missing length(l)

So:

378=7*9*l

To find length(l), we must iscolate it.

To do this, we must get rid of the 7 and 9.

So lets start by dividing 378 by 9:

378/9=7*9/9*l

=

42=7*l

Now lets do the same thing with the 7 to iscolate l:

42/7=7/7*l

=

6=l

So our missing length(l) is 6.

Answer:

l = 6

Hope this helps!

5 0
3 years ago
Combine like terms to create an equivalent expression.
Lelu [443]

Answer:

\frac{1}{6} p - \frac{4}{5}

Step-by-step explanation:

collect like terms

- \frac{2}{3} p + \frac{5}{6} p + \frac{1}{5} - 1

= - \frac{2(2)}{2(3)} p + \frac{5}{6} p + \frac{1}{5} - \frac{5}{5}

= - \frac{4}{6} p + \frac{5}{6} p - \frac{4}{5}

= \frac{1}{6} p - \frac{4}{5}

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2 years ago
The points plotted below are on the graph of a polynomial. In what range of
Irina-Kira [14]

Answer:

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3 years ago
HELPP AND. D IS 10 it got cut out
Inga [223]

Answer: 2

Step-by-step explanation:

2

7 0
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Read 2 more answers
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