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lions [1.4K]
1 year ago
12

Which choice most effectively combines the

Mathematics
1 answer:
Thepotemich [5.8K]1 year ago
7 0

The Choice D is the best answer by the passage because it most clearly and concisely combines the sentences using the correct punctuation. This choice eliminates unnecessary words, and the commas are placed correctly between the clauses.

According to the statement

we have to find that the out of given options which is correct for replace the words in the passage.

So, For this purpose, we know that the

In the passage ,

Choice A is incorrect because the phrase “the result being that it” is wordy and could be replaced with the single word “which.” Choice B is incorrect because the words “algal blooms cause oxygen depletion” need not be repeated. Choice C is incorrect because there is unnecessary repetition of the words “oxygen depletion” and “algal blooms.”

So, The Choice D is the best answer by the passage because it most clearly and concisely combines the sentences using the correct punctuation. This choice eliminates unnecessary words, and the commas are placed correctly between the clauses.

Learn more about passage here

brainly.com/question/12555695

#SPJ4

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Big chickens: The weights of broilers (commercially raised chickens) are approximately normally distributed with mean 1387 grams
Nataliya [291]

Answer:

a) 0.2318

b) 0.2609

c) No it is not unusual for a broiler to weigh more than 1610 grams

Step-by-step explanation:

We solve using z score formula

z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

Mean 1387 grams and standard deviation 192 grams. Use the TI-84 Plus calculator to answer the following.

(a) What proportion of broilers weigh between 1150 and 1308 grams?

For 1150 grams

z = 1150 - 1387/192

= -1.23438

Probability value from Z-Table:

P(x = 1150) = 0.10853

For 1308 grams

z = 1308 - 1387/192

= -0.41146

Probability value from Z-Table:

P(x = 1308) = 0.34037

Proportion of broilers weigh between 1150 and 1308 grams is:

P(x = 1308) - P(x = 1150)

0.34037 - 0.10853

= 0.23184

≈ 0.2318

(b) What is the probability that a randomly selected broiler weighs more than 1510 grams?

1510 - 1387/192

= 0.64063

Probabilty value from Z-Table:

P(x<1510) = 0.73912

P(x>1510) = 1 - P(x<1510) = 0.26088

≈ 0.2609

(c) Is it unusual for a broiler to weigh more than 1610 grams?

1610- 1387/192

= 1.16146

Probability value from Z-Table:

P(x<1610) = 0.87727

P(x>1610) = 1 - P(x<1610) = 0.12273

≈ 0.1227

No it is not unusual for a broiler to weigh more than 1610 grams

8 0
3 years ago
The functions f(x) and g(x) are shown on the graph. F(x)= x^2 <br> What is g(x)
bearhunter [10]

Answer:

I think the answer would be A

4 0
3 years ago
Need help please cant understand this probplem
klasskru [66]

Answer:

No solution

Step-by-step explanation:

Distribute the right side of the equation.

This will make it 3/8f+1/2=3/8f - 18

And, since 3/8f plus 1/2 will never equal the same thing as 3/8f minus 18, there are no solutions

4 0
3 years ago
Read 2 more answers
Find the surface area of the right prism. Round to the nearest whole number.
andriy [413]

Answer:

\large\boxed{S.A.=96\ cm^2}

Step-by-step explanation:

We have:

(1) two trapezoids with bases b₁ = 7cm and b₂ = 5cm and the height h = 4cm

(2) three rectangles 3 cm × 7 cm, 3 cm × 4 cm and 3 cm × 5 cm.

The formula of an area of a trapezoid:

A=\dfrac{b_1+b_2}{2}\cdot h

Substitute:

A=\dfrac{7+5}{2}\cdot4=24\ cm^2

Calculate the areas of the rectangles:

A_1=(3)(7)=21\ cm^2\\\\A_2=(3)(4)=12\ cm^2\\\\A_3=(3)(5)=15\ cm^2

The Surface Area:

S.A.=(2)(24)+21+12+15=96\ cm^2

5 0
3 years ago
Solve for 7 and 8 please
Masteriza [31]
To divide exponents they have to have the same base and then you just subtract the bottom exponent from the top exponent.

7) k × 3^9
----------- =
3^5

k × 3^9-5 =
k × 3^4 =
k × 81 = 81k

8) x^4 × y^10 × 2^11
------------------------ =
y^8 × 2^7

x^4 × y^10-8 × 2^11-7 =
x^4 × y^2 × 2^4 =
x^4 × y^2 × 16=
16x^4y^2
8 0
3 years ago
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