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docker41 [41]
1 year ago
5

Beth left school driving toward the lake one hour before tim. tim drove in the opposite direction going 6 mph slower than beth f

or one hour after which time they were 174 miles apart. what was beths speed? and please explain thoroughly and take me through the process.
Mathematics
1 answer:
m_a_m_a [10]1 year ago
3 0

Beth's speed was 60 mph.

<h3>What is speed?</h3>
  • The speed (commonly referred to as v) of an object in everyday use and kinematics is the magnitude of the change in its position over time or the magnitude of the change in its position per unit of time; it is thus a scalar quantity.
  • The distance traveled by an object in a time interval is divided by the duration of the interval; the instantaneous speed is the limit of the average speed as the duration of the time interval approaches zero.
  • Velocity is not the same as speed.

To find what was Beth's speed:

Beth's data:

  • time = 2 hrs; rate = r mph; distance = r×t = 2r miles

Tim's data:

  • time = 1 hr; rate = r-6 mph; distance = r-6 miles

Equation:

  • distance + distance = 174 miles

So,

  • 2r + r - 6 = 174
  • 3r - 6 = 174
  • 3r = 180
  • r = 60 mph (Beth's rate)
  • r-6 = 54 mph (Tims's rate)

Therefore, Beth's speed was 60 mph.

Know more about speed here:

brainly.com/question/4931057

#SPJ4

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Likurg_2 [28]

Answer:

The solution is (0, 3/4)

Step-by-step explanation:

Please copy and share the instructions.  Here they are:  Solve the following system of linear equations.

Both of the equations can be reduced (simplified):

2x+8y = 6            =>  x + 4y = 3

15x + 20y = 15     => 3x + 4y = 3

Let's use the elimination by addition and subtraction method.  Multiply the first equation by -1, obtaining

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equation to the

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We get:                       2x = 0.

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The solution is (0, 3/4).

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<span>-6(-5)+12
Multiply -6 by -5.
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4 0
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Length of a rectangle is 5 cm longer than the width. Four squares are constructed outside the rectangle such that each of the sq
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Answer:

18

Step-by-step explanation:

Remark

This is one of those questions that can throw you. The problem is that do you include the original rectangle or not. The way it is written it sounds like you shouldn't

However if you don't the question gives you 2 complex answers. (answers with the sqrt( - 1) in them.

Solution

Let the width = x

Let the length = x + 5

Area of the rectangle: L * w = x * (x + 5)

Area of the smaller squares (there are 2)

Area = 2*s^2

x = s

Area = 2 * x^2

Area of the larger squares = 2 * (x+5)^2

Total Area

x*(x + 5) + 2x^2 + 2(x + 5)^2 = 120                 Expand

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x^2 + 5x + 2x^2 + 2x^2 + 20x + 50 = 120      collect the like terms on the left

5x^2 + 25x +  50 = 120                                   Subtract 120 from both sides.

5x^2 + 25x - 70 = 0                                         Divide through by 5

x^2 + 5x - 14 = 0                                               Factor

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x = 2                                                              

Perimeter

P = 2*w + 2*L

w = 2

L = 2 + 5

L = 7

P = 2*2 + 2 * 7

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P = 18

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olchik [2.2K]

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Let plug in the formula

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Policy expected value=$1,300-($615+$$400)

Policy expected value=$1,300-$1,015

Policy expected value=$285.00

Inconclusion the expected value of this policy to the insurance company is $285.00

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Answer:

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