Answer:
The area of triangle K is 16 times greater than the area of triangle J
Step-by-step explanation:
we know that
If Triangle K is a scaled version of Triangle J
then
Triangle K and Triangle J are similar
If two triangles are similar, then the ratio of its areas is equal to the scale factor squared
Let
z -----> the scale factor
Ak ------> the area of triangle K
Aj -----> the area of triangle J
so

we have

substitute



therefore
The area of triangle K is 16 times greater than the area of triangle J
Answer:
Step-by-step explanation:
(3b)³ = 3³·b³ = 27b³
30 or 3 and 4 weeks hope this helps

The given angles forms linear pair, and we know the angles forming linear pair are supplementary,
Therefore,
Angle MHJ + Angle MHL = 180°
Let's solve :
Value of variable m = 10°

Answer:
16:12
Step-by-step explanation:
(4+12)=16
16/4 = 4
4x3=12
Another method:
4---------3
16-------x
Cross multiplication
4x=16x3
4x=48
x=12