Answer:
13
Step-by-step explanation:
To find the range substitute the value of x from the domain into the equation.
x = - 2 : y = -5(- 2) + 3 = 10 + 3 = 13
x = 0 : y = - 5(0) + 3 = 0 + 3 = 3
x = 1 : y = - 5(1) + 3 = - 5 + 3 = - 2
x = 3 : y = - 5(3) + 3 = - 15 + 3 = - 12
range is { - 12, - 2, 3, 13 }
with greatest value in the range being 13
I’m assuming you mean -1/4 -4, and since you’re subtracting a negative by a negative, it would be -4 1/4(mixed number)
16x + 64
Hope this helps:)
You would would you the measurement of one cup
We can solve this problem using discriminant.
x^2-4x-12's discriminant is
(-4)^2-4*-12=16+48 which is clearly larger than 0
This means that it crosses over the axes 2 times.
In case you don't know what discriminant is, its in equation ax^2+bx+c
the discriminant is b^2-4ac.
If its positive it has 2 crosses with x axis, if negative then 0 crosses, if 0 then 1 cross.
Hope this helped at least a little bit :D
