According to the confidence interval only persons who watch at least 9.9 hours TV per day are eligible.
According to the statement
we have given that the mean of 7 hours per day watching TV, and a standard deviation of 1.8 hours.
And we have to find that the At least how many hours of daily TV watching are necessary for a person to be eligible for the interview.
So, For this purpose,
The confidence interval is is a range of estimates for an unknown parameter. A confidence interval is computed at a designated confidence level.
Let us Assume x is the amount of hours that 5% of the persons exceeds.
Then P(z<(x-7)/1.8) = 0.95
From a standard normal table, we know that:
(x-7)/1.8 = 1.6449
x-7 = 2.9607
x = 9.9607
So, According to the confidence interval only persons who watch at least 9.9 hours TV per day are eligible.
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Poor kid, next time ask your parents or teacher for help or try to find a smart friend that can help you. Go to bed if it is late and make sure you understand your homework before taking it home. Good luck!! :))
Answer:
Solution given;
a⁴-23a²b²+b⁴
making in the form of a²+2ab+b²
a⁴+2a²b²+b⁴-2a²b²-23a²b²
(a²+b²)²-(5ab)²
factoring by using formula
x²-y²=(x+y)(x-y)
<u>(a²+5ab+b²)(a²-5ab+b²)</u>
Toatl calories is 49.
She ate 1 during the day, so subtract 1 from the total to find how many calories she needs from her snacks :
49 -1 = 48 calories.
Each snack is 24 calories, so divide the number of calories she needs by 24 to find the number of snacks:
48 calories / 24 calories per snack = 2 snacks.
She needs to eat 2 late night snacks.