Answer:
The lines DE and BC have the same slope, therefore the two lines, DE and BC, are parallel
Step-by-step explanation:
To prove that DE is parallel to BC, we have;
The slope, m of the lines DE and BC are found from the following equation;
Where;
(x₁, y₁) and (x₂, y₂) = (b, c) and (a + b + c) for DE, we have;
Where we have (x₁, y₁) and (x₂, y₂) = (0, 0) and (2a, 0) for BC, we have;
Therefore, because the lines DE and BC have the same slope, the two lines DE and BC are parallel.
Answer:
(-6,4)
Step-by-step explanation:
If this is the system of equations here is how:
solve for 1 vairuble in the first equation, and plug that it to the other.
Answer:
I see two triangles
Step-by-step explanation:
Answer:
2/3( x^2 + 5 ) = 14 or 2/3x^2 - 32/3
Step-by-step explanation:
Part 1:
Two-thirds ( 2/3 )
of the ( (---) )
sum ( + )
of a number squared ( x^2 ) and 5 ( + 5 )
is fourteen ( = 14 )
Part 2 (Not super confident about):
2/3( x^2 + 5 ) = 14
2/3x^2 + 10/3 = 14
2/3x^2 - 32/3
Hopefully this helps!
Brainliest please?
Answer:
6
Step-by-step explanation:
