Vertex form is
y=a(x-h)^2+k
vertex is (h,k)
axis of symmetry is x=4, therfor h=4
y=a(x-4)^2+k
we have some points
(3,-2) and (6,-26)
input and solve for a and k
(3,-2)
-2=a(3-4)^2+k
-2=a(-1)^2+k
-2=a(1)+k
-2=a+k
(6,-26)
-26=a(6-4)^2+k
-26=a(2)^2+k
-26=a(4)+k
-26=4a+k
we have
-2=a+k
-26=4a+k
multiply first equation by -1 and add to second
2=-a-k
<u>-26=4a+k +</u>
-24=3a+0k
-24=3a
divide both sides by 3
-8=a
-2=a+k
-2=-8+k
add 8 to both sides
6=k
the equation is
Answer:
i think it's 51 because if you add 106 and 23 together it's 129 then 180-129= 51
Step-by-step explanation:
Answer:
<span>⇒x=9</span> (positive solution)
Explanation:
<span><span>x2</span>−36=5x</span>
<span>→<span>x2</span>−36−5x=0</span>
Factor the expression:
We get:
<span><span>(x−9)</span><span>(x+4)</span>=0</span>
First solution:
<span>⇒<span>(x−9)</span>=<span>0<span>x+4</span></span></span>
<span>⇒<span>(x−9)</span>=0</span>
<span>⇒x=<span>9</span></span>
Hello :
the terme general is : an = a1 +(n-1)d
a11 = a1+(11-1)×5
a11 = -12+50
a11 = 38
<span>the sum of the first 11 terms is : S11 = (11/2)(a1+a11)
</span>S11 = (11/2)(-12+38)
S11 = 143