It would be true because 10,000-99,999=-89999 -89999<0 is true
Answer:
The answer is -4
Step-by-step explanation:
Hope this helps! :)
Answer:
504 kilos de manzanas fueron llevados a la escuela.
Step-by-step explanation:
Sean
,
la cantidad de cajas de manzanas y peras, respectivamente. De acuerdo con el enunciado, tenemos el siguiente sistema de ecuaciones:
Total de cajas
(1)
Masa de cada caja de peras
(2)
(3)
Masa de caja de manzanas
(4)
De (2) en (3), tenemos que la masa de cada caja de peras es:

Por (4), encontramos que la masa de cada caja de manzanas es:


Finalmente, de (1) tenemos la cantidad de cajas de manzana:


La cantidad de kilos de manzanas llevada a la escuela se obtiene al multiplicar la cantidad de cajas de manzana por la masa de cada caja:


504 kilos de manzanas fueron llevados a la escuela.
5/8 and 2/3 so...
8 times 3 is 24 so now put your fraction over twenty four
15/24=5/8
15/24 so fifteen out of twenty fourths of the package is what she has. She takes ten out of the fifteenths because fifteen divided by three is five then multiply by two is ten. Then divide by five and you get two.
15/24. 10-> 15/24 cause... 15 divided by 3 ( from the two thirds she cooked) is 5 then * by 2... 5*2=10
Answer:
The first graph best represent the given scenario.
Step-by-step explanation:
Given that Kent walked to the bus stop, then sat and waited until the bus arrived. He rode the bus for 25 minutes, then walked the last 3 blocks to work. we have to find which graph best represent the scenario.
In the first graph, it is given The line increases for 10 minutes means the distance as well as time increases i.e Kent walked for 10 minutes then, stays horizontal for 15 minutes means no distance covered i.e stop or wait for 15 minutes. After that graph increases rapidly for another 25 minutes, that means rode the bus for 25 minutes then increases slowly for 5 minutes indicate walked to work.
The above graph best represent the scenario.
All three option is analysed by graphing which doesn't show the above given scenario.