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sdas [7]
2 years ago
9

If k(x) = x^2 and p(x) = k(x) + n, what is the value of n?

Mathematics
1 answer:
kodGreya [7K]2 years ago
8 0

Answer:

The value of n is -6

Step-by-step explanation:

  • If the function f(x) is translated k units up, then its image is g(x) = f(x) + k
  • If the function f(x) is translated k units down, then its image is g(x) = f(x) - k
  • The vertex form of the quadratic function is f(x) = a(x - h)² + k, where a is the coefficient of x² and (h, k) is the vertex

∵ k(x) = x²

→ Its graph is a parabola with vertex (0, 0)

∴ The vertex of the prabola which represents it is (0, 0)

∵ The given graph is the graph of p(x)

∵ Its vertex is (0, -6)

∴ h = 0 and k = -6

∵ a = 1

→ Substitute them in the form above

∴ p(x) = 1(x - 0)² + -6

∴ p(x) = x² - 6

→ Substitute x² by k(x)

∴ p(x) = k(x) - 6

∵ p(x) = k(x) + n

→ By comparing the two right sides

∴ n = -6

∴ The value of n is -6

Look at the attached figure for more understanding

The red parabola represents k(x)

The blue parabola represents p(x)

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To find differences in the angles of the intersections we must know how many degrees each angle corresponds to. We must also take into account that the sum of the internal angles must equal 180°.

<h3>What is a triangle?</h3>

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