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sdas [7]
2 years ago
9

If k(x) = x^2 and p(x) = k(x) + n, what is the value of n?

Mathematics
1 answer:
kodGreya [7K]2 years ago
8 0

Answer:

The value of n is -6

Step-by-step explanation:

  • If the function f(x) is translated k units up, then its image is g(x) = f(x) + k
  • If the function f(x) is translated k units down, then its image is g(x) = f(x) - k
  • The vertex form of the quadratic function is f(x) = a(x - h)² + k, where a is the coefficient of x² and (h, k) is the vertex

∵ k(x) = x²

→ Its graph is a parabola with vertex (0, 0)

∴ The vertex of the prabola which represents it is (0, 0)

∵ The given graph is the graph of p(x)

∵ Its vertex is (0, -6)

∴ h = 0 and k = -6

∵ a = 1

→ Substitute them in the form above

∴ p(x) = 1(x - 0)² + -6

∴ p(x) = x² - 6

→ Substitute x² by k(x)

∴ p(x) = k(x) - 6

∵ p(x) = k(x) + n

→ By comparing the two right sides

∴ n = -6

∴ The value of n is -6

Look at the attached figure for more understanding

The red parabola represents k(x)

The blue parabola represents p(x)

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