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Mazyrski [523]
1 year ago
11

Solve x≤0 and x≥−4 and write the solution in interval notation. If there is no solution, type ∅.

Mathematics
1 answer:
xxTIMURxx [149]1 year ago
5 0

The answer is (-∞.∞).

Draw out a number line. Plot 0 and -4 on the number line.

Shade to the left of x = 0, and have a filled in circle at the endpoint. This is the graph of x≤0

Then graph x ≥−4 by plotting a filled in circle at -4, and shading to the right.

Note how the two graphs overlap to cover the entire real number line

So if we have x≤0  or  x≥−4 then we're basically saying x is any real number. To write this in interval notation, we write (−∞,∞)

This is the interval from negative infinity to positive infinity (or just infinity). We exclude each endpoint because we can't actually reach infinity itself. Infinity is not a number. Infinity is a concept

Side note: if you change the "or" to "and", then the solution to x≤0  and  x≥−4 would be [-4, 0][−4,0] to indicate the interval from x = -4 to x = 0, including both endpoints. This is the region where the two graphs overlap.

To know more about graphs

visit-:brainly.com/question/10712002

SPJ9

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Which point lies on the graph of y = -|x| -5?​
uysha [10]

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3 years ago
Which equations represent the line that is perpendicular to the line 5x − 2y = −6 and passes through the point (5, −4)? Check al
Alla [95]

Let's rewrite each equation in the Slope-Intercept Form of the Equation of a Line. First, let's start with the main equation:


\bullet \ 5x-2y=-6 \therefore y=\frac{5}{2}x+3


Then, our options are the following:

A) \ y = -\frac{2}{5}x-2 \\ \\ B) \ 2x+5y=-10 \therefore y=-\frac{2}{5}x-2 \\ \\ C) \ 2x-5y=-10 \therefore y=\frac{2}{5}x+2 \\ \\ D) \ y+4=-\frac{2}{5}(x-5) \therefore y=-\frac{2}{5}x-2 \\ \\ E) \ y-4=\frac{5}{2}(x + 5) \therefore y=\frac{5}{2}x+\frac{33}{2}


For two perpendicular lines it is true that the product of its slopes is:

m_{1}m_{2}=-1


m_{1}m_{2}=-1 \\ \\ m_{1} \ is \ the \ slope \ of \ y=\frac{5}{2}x+3, \ that \ is, \ m_{1}=\frac{5}{2} \\ \\ Then, \ the \ slope \ of \ a \ perpendicular \ line \ is: \\ \\ m_{2}=-\frac{2}{5}


According to this, only A) B) and D) might be the perpendicular lines we are looking for. Notice that these lines are the same. The other condition is that the line must pass through the point (5, -4). By substituting this point in the equation, we have:

y = -\frac{2}{5}x-2 \\ \\ -4=-\frac{2}{5}(5)-2 \\ \\ -4=-2-2 \\ \\ \boxed{-4=-4} \ True!


Finally, the right answer are:

A) \ y = -\frac{2}{5}x-2 \\ \\ B) \ 2x+5y=-10 \\ \\ D) \ y+4=-\frac{2}{5}(x-5)

8 0
2 years ago
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irina [24]
51:75

This is the same as 51/75.

Simplify by dividing 3 to the numerator and denominator:

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Divide this to get a decimal:

17 / 25 = 0.68

Now multiply by 100 to get a percent:

0.68 * 100 = 68%
6 0
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