D) 38 feet hope this helped just in time

In 1993, Moose Population: 3280
In 1999, population became: 4960
P (Population) , t (years)
t = 6 —> 4960 - 3280 = 1680
Average Change —> 1680/6 = 280 moose/year
• In terms of 1990:
t = 3 —> 3280-3 (280)
P(1990) = 2440
P(t) = 2440 + 280t
• In 2003; t = 13
P(13) = 2440 + 280 (13)
P(13) = 2440 + 3640
P(13) = 6080
• Moose population in 2003
= 6080
Answer:
21
Step-by-step explanation:
Because...
Use the cross multiplication method. 768.57 over 41.1= x/1 768.57 times 1=768.57 41.1 times x=41.1x 768.57/41.1=x x=18.7 18.7mph