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iren [92.7K]
3 years ago
7

Create a system of equations with a solution of (4,1)

Mathematics
1 answer:
Pani-rosa [81]3 years ago
4 0

Answer:

x + y = 5 (or) xy = 4 (or) x - y = 3

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SOLVE THIS QUESTION<br>​
ASHA 777 [7]

447/250

is the answer to the question

4 0
3 years ago
Read 2 more answers
Joel made egg sandwiches and tuna sandwiches in the ratio 2:3. He then made 15 more tuna sandwiches and the ratio changed to 1:3
Aleksandr [31]

Answer:

40 sandwiches

Step-by-step explanation:

egg sandwiches : tuna sandwiches

 2                         : 3

Multiply by x  because we do not know how many sandwiches, just the ratio

2x                       : 3x


Add 15  tuna sandwiches

2x                       : 3x+15

Now the ratio is 1:3


egg sandwiches : tuna sandwiches

 1                         : 3

Multiply by y  because we do not know how many sandwiches, just the ratio

y                           : 3y


Set the number of egg sandwiches equal

2x =y

then set the number of tuna sandwiches equal

3x+15 = 3y

We know have a system of 2 equations and 2 unknowns

Substitute y =2x into the second equation

3x+15 = 3(2x)

Distribute

3x+15 = 6x

Subtract 3x from each side

3x-3x+15 = 6x-3x

15 =3x

Divide by 3

15/3 = 3x/3

5 =x


egg sandwiches : tuna sandwiches

 2                         : 3

Multiply by x  because we do not know how many sandwiches, just the ratio

2x                       : 3x

2*5                        3*5

10                             15


He originally made 10 egg sandwiches and 15 tuna sandwiches

Then he made 15 more tuna sandwiches

The total number of sandwiches he made is

10+15+15 = 40 sandwiches  




5 0
3 years ago
Determine the equations of the vertical and horizontal asymptotes, if any, for y=x^3/(x-2)^4
djverab [1.8K]

Answer:

Option a)

Step-by-step explanation:

To get the vertical asymptotes of the function f(x) you must find the limit when x tends k of f(x). If this limit tends to infinity then x = k is a vertical asymptote of the function.

\lim_{x\to\\2}\frac{x^3}{(x-2)^4} \\\\\\lim_{x\to\\2}\frac{2^3}{(2-2)^4}\\\\\lim_{x\to\\2}\frac{2^3}{(0)^4} = \infty

Then. x = 2 it's a vertical asintota.

To obtain the horizontal asymptote of the function take the following limit:

\lim_{x \to \infty}\frac{x^3}{(x-2)^4}

if \lim_{x \to \infty}\frac{x^3}{(x-2)^4} = b then y = b is horizontal asymptote

Then:

\lim_{x \to \infty}\frac{x^3}{(x-2)^4} \\\\\\lim_{x \to \infty}\frac{1}{(\infty)} = 0

Therefore y = 0 is a horizontal asymptote of f(x).

Then the correct answer is the option a) x = 2, y = 0

3 0
3 years ago
Read 2 more answers
3. ms. Johnson placed two different orders with TR's special item store. each order was for 40 jars with the circus logo imprint
denis23 [38]
1.The height is 6 inches ad the width (diameter) is 3 inches!
2. So the jars are Volume ≈  42.41 inches so each boy needs 200 / 42.41 which equals approximately 4.72 inches per jar. So if wach boys have half the amount of jars which is 20 you multiply 20 by 4.72 which is 94.4 inches for each boy!
3 0
3 years ago
Find the area of the shaded polygon:<br><br> PLS JUST ANSWER
timofeeve [1]

Answer:

9 square units

Step-by-step explanation:

1/2(3)=1.5

1/2(6)=3

2

1/2(3)=1.5

1/2(2)=1

1.5+1.5+3+2+1=9

7 0
3 years ago
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