Area of the figure = 806.5 in²
Solution:
Length of the rectangle = 16 in
Breadth of the rectangle = 9 in
Area of the rectangle = length × breadth
= 16 × 9
Area of the rectangle = 144 in²
Base of the triangle = 31 in
Height of the triangle = 20 in
Area of the triangle = 
Area of the triangle = 310 in²
Parallel sides of the trapezium = 16 in and 31 in
Height of the trapezium = 35 – 20 = 15 in
Area of the trapezium = 
Area of the trapezium = 352.5 in²
Area of the figure = Area of rectangle + Area of triangle + Area of trapezium
= 144 in² + 310 in² + 352.5 in²
Area of the figure = 806.5 in²
Arranging in ascending order we have
52 55 59 60 62 65 65 66
The median = (60+62)/2 = 61
The mean = 484 / 8 = 60.5
range = 66-52 = 14
interquartile range = 65 - 57 = 8
pairs = 65
Answer:
(13.5, 34.5)
Step-by-step explanation:
The empirical rule states that for a normal distribution, the data will fall within three standard deviations of the mean. 68% of the data falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).
Given that mean (µ) = 24 and standard deviation (σ) = 3.5
Using empirical rule, the interval that represents the middle 99.7% = (µ ± 3σ) = (24 ± 3*3.5) = (13.5, 34.5)
Answer:
8
Step-by-step explanation:
Let the width of the rectangle be x. Then the length would be x+2
Area=(length)*(width)
48=x(x+2), => x=6. Width is 6 and length is 8
