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pshichka [43]
2 years ago
14

Match the reasons with the statements in the proof.

Mathematics
2 answers:
bija089 [108]2 years ago
8 0

Answer:

Step-by-step explanation:

1. m∠6 = m∠8, b║c

Given

2. m∠7 = m∠8

It is given that b and c are parallel therefore, ∠7 and ∠8 are the corresponding angles.

3. m∠6 = m∠7

Since ∠6 = ∠8 and ∠7 = ∠8

Therefore, ∠6 = ∠7

Substitution

4. a║b

Since ∠6 = ∠7 (alternate interior angles) so lines a and b will be parallel.

natta225 [31]2 years ago
6 0
<span>1. m∠6=m∠8, b||c
Given

2. m∠7=m∠8
</span><span>If lines ||, corresponding angles =.
</span><span>
3. m∠6=m∠7
</span>Substitution 
<span>
4. a||b </span>
If alternate interior angles equal, then lines ||. 
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Answer:

Choice b.

x^{2} + 5\, x + 6 = (x + 3)\, (x + 2).

Step-by-step explanation:

The highest power of the variable x in this polynomial is 2. In other words, this polynomial is quadratic.

It is thus possible to apply the quadratic formula to find the "roots" of this polynomial. (A root of a polynomial is a value of the variable that would set the polynomial to 0.)

After finding these roots, it would be possible to factorize this polynomial using the Factor Theorem.

Apply the quadratic formula to find the two roots that would set this quadratic polynomial to 0. The discriminant of this polynomial is (5^{2} - 4 \times 1 \times 6) = 1.

\begin{aligned}x_{1} &= \frac{-5 + \sqrt{1}}{2\times 1} \\ &= \frac{-5 + 1}{2} \\ &= -2\end{aligned}.

Similarly:

\begin{aligned}x_{2} &= \frac{-5 - \sqrt{1}}{2\times 1} \\ &= \frac{-5 - 1}{2} \\ &= -3\end{aligned}.

By the Factor Theorem, if x = x_{0} is a root of a polynomial, then (x - x_0) would be a factor of that polynomial. Note the minus sign between x and x_{0}.

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Verify that (x + 2)\, (x + 3) indeed expands to the original polynomial:

\begin{aligned}& (x + 2)\, (x + 3) \\ =\; & x^{2} + 2\, x + 3\, x + 6 \\ =\; & x^{2} + 5\, x + 6\end{aligned}.

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