we conclude that the solution for the given algebraic expressions are:
- J = -5
- s = -106
- t = 38
- r = -60
- a = 57
<h3>
How to solve these algebraic expressions?</h3>
Here we have some simple algebraic expressions:
The first one is:
-25/J = 5
We want to solve this for J.
Remember that we can perform the same operation in both sides of the equation, then we cans tart by multiplying both sides by J.
(-25/J)*J = 5*J
-25 = 5*J
Now we can divide both sides by 5, so we isolate J:
(-25)/5 = (5*J)/5
-5 = J
We conclude that the solution is J = -5.
Now, similarly for the other equations we have that:
16 + s = -90
Here we subtract 16 in both sides:
s = -90 - 16 = -106
13 + t = 51
Here we subtract 13 in both sides:
t = 51 - 13 = 38
r/10 = (-6)
Here we multiply both sides by 10:
r = (-6)*10 = -60
a + (-12) = 45
Here we add 12 in both sides:
a = 45 + 12 = 57
Then we conclude that the solution for the given algebraic expressions are:
- J = -5
- s = -106
- t = 38
- r = -60
- a = 57
If you want to learn more about algebraic expressions:
brainly.com/question/4344214
#SPJ1
Answer:
y =1/2x+6
y = -2x+2
Step-by-step explanation:
Perpendicular line have slopes that multiply to -1
The slopes are negative reciprocals
-4*4 = 16 not perpendicular
1/2 * -2 = -1 perpendicular
1/5 *5 = 1 not perpendicular
2/3 * 2/3 = 4/9 not perpendicular
91.8642; multiplying by 1/10 is the same as dividing by 10. To divide a number by 10, you just move the decimal point one place to the left.
Substitute either set of points into the equation:
(3, -1) and (-6,-4)
-1= -5/9(3)+b
-1= -15/9+b
-1+5/3= -5/3 +5/3 +b
2/3=b
So,
f(x)= -5/9 (x) + 2/3
