Building time :
4c + 6a < = 120
testing time :
4c + 4a < = 100
20 child bikes and 6 adult bikes...c = 20 and a = 6
sub into both equations
4c + 6a < = 120
4(20) + 6(6) < = 120
80 + 36 < = 120
116 < = 120 (correct)
4c + 4a < = 100
4(20) + 4(6) < = 100
80 + 24 < = 100
104 < = 100 (incorrect)
ur answer : No, because the bike order does not meet the restrictions of 4c + 6a < = 120 and 4c + 4a < = 100
Simplify. Combine like terms
12x - 9x = 3x
7 - 15 = -8
3x - 8 is your answer
hope this helps
Hey!
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Answer: Yes 3/6 is rational!
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Why? Well, because 3 and 6 are integers that don't repeat. 3/6 simplifies to 1/2 or 0.5 which doesn't repeat so it's rational.
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Hope This Helped! Good Luck!
I think that would be the Chytridiomycota fungi
Answer:
The value of x must be greater than 100.
Step-by-step explanation:
We need to find the value x for which the value of log(x) is greater than than 2.

According to the property of logarithm, if a is a real number.

Using the above property of logarithm, the given inequality can be rewritten as


We conclude that the value of log(x) is greater than 2 for real values of x which are greater than 100.
Therefore, the value of x must be greater than 100.