We have been given two expressions 
. We are asked to find the value of each.
To find 9P9, we will use permutations formula.
, where
P = Number of permutations,
n = The total number of objects in the set,
r = Number of objects being chosen from the set.
Using 
To find 9C9, we will use combinations formula.
, where
C = Number of combinations,
n = The total number of objects in the set,
r = Number of objects being chosen from the set.
Using
Cancelling out 
, we will get:
The answers differ because order. With permutations we care about the order of the elements, while with combinations we don't.
<span>365000 i think......</span>
The standard form of a quadratic equation is
, while the vertex form is:
, where (h, k) is the vertex of the parabola.
What we want is to write
as
First, we note that all the three terms have a factor of 3, so we factorize it and write:
.
Second, we notice that
are the terms produced by
, without the 9. So we can write:
, and substituting in
we have:
![\displaystyle{ y=3(x^2-6x-2)=3[(x-3)^2-9-2]=3[(x-3)^2-11]](https://tex.z-dn.net/?f=%5Cdisplaystyle%7B%20y%3D3%28x%5E2-6x-2%29%3D3%5B%28x-3%29%5E2-9-2%5D%3D3%5B%28x-3%29%5E2-11%5D)
.
Finally, distributing 3 over the two terms in the brackets we have:
![y=3[x-3]^2-33](https://tex.z-dn.net/?f=y%3D3%5Bx-3%5D%5E2-33)
.
Answer:
Answer: first question answer is 3x^3+6x^2-24x+27
Second question answer=a^2-ab
Step-by-step explanation:
