Answer: (y-3)^2= 52(x+7)
The focus is (-10, -7) and the directrix is x=16. The y-coordinate of the vertex should be same as the focus(k=-7). Then the x-coordinate of the vertex would be:
p + (-10)= 16 - p
2p= 16 + 10
p=26/2= 13
The x-coordinate of the vertex would be:
h= p+ (-10)
h= 13 - 10= 3
The vertex coordinate would be: (h, k)= (3, -7)
For a vertex (h, k), the formula for equation would be
(y-k)^2=4 p(x-h)
(y-3)^2= 4*13(x--7)
(y-3)^2= 52(x+7)
Well from what I understand about the question, it's asking if there only needs to be 1, how many can there be. so 9
Well if 3+2 is 5 then the bowling alley should be free?
Yes they are prime if that's the question u just asked
Answer: 0.57
It’s out of 100, so it’s 57 hundredths
