100,000? because .000157 is a decimal, right?
Please give the options in order for us to determine which is best.
Answer:
C. $65,800
Explanation:
Fixed csot: those which do not change for a relevant range with the production output. They aer constant.
Factory insurance 21,000
Factory insurance 13,000
Factory manager's salary 10,800
Janitor's salary 5,000
Property taxes: <u> 16,000 </u>
Total Fixed Cost: 65,800
The direct materials and direct labor are variable cost as they drop to zero if no unit is produced.
Same goes with packaging cost, if no unit is produced then, no packagin is needed.
Answer:
Equilibrium Price - 3
Equilibrium Quantity - 3
Explanation:
The price at which there will be equilibrium in the chocolate market is 3 units while the corresponding quantity is also 3 units.
<u>The equilibrium price and quantity represents the price and quantity where the demand for a product is equal to the supply for the same product respectively.</u>
<em>In the graph, the point of intersection of the demand and the supply curve represents the equilibrium point. At this point, the price on the Y axis is 3 units while the corresponding quantity on the X axis is also 3 units.</em>
Answer:
a) H0: u = presence of a unit root
HA: u ≠ presence of a unit root ( i.e. stationary series )
b) t stat = -0.064
c) We will reject the Null hypothesis and the next step will be to accept the alternative hypothesis
d) It is not valid to compare the estimated t stat with the corresponding critical value because a random walk is non-stationary while the difference is stationary because it is white noise
Explanation:
<u>a) stating the null and alternative hypothesis</u>
H0: u = presence of a unit root
HA: u ≠ presence of a unit root ( i.e. stationary series )
<u>b) performing the test </u>
critical value = -2.88
T stat = coefficient / std error
= -0.02 / 0.31 = -0.064
c) From the test, the value of T stat > critical value we will reject the Null hypothesis hence the next step will be to accept the alternative hypothesis
d) It is not valid to compare the estimated t stat with the corresponding critical value because a random walk is non-stationary while the difference is stationary because it is white noise
